unzip | 易学教程

How to read content of the Zipped file without extracting in java

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问题 I have file with names like ex.zip . In this example, the Zip file contains only one file with the same name(ie. `ex.txt'), which is quite large. I don't want to extract the zip file every time.Hence I need to read the content of the file(ex.txt) without extracting the zip file. I tried some code like below But i can only read the name of the file in the variable. How do I read the content of the file and stores it in the variable? Thank you in Advance fis=new FileInputStream("C:/Documents

How can unrar a file with python

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I can to unzip a file if file is a .zip and unrar file if my file type is .rar . How i can do this work with python 2.7? Irakli Darbuashvili Try the pyunpack package: from pyunpack import Archive Archive('a.zip').extractall('/path/to') lelouch Late, but I wasn't satisfied with any of the answers. pip install patool import patoolib patoolib.extract_archive("foo_bar.rar", outdir="path here") Works on Windows and linux without any other libraries needed. A good package for it is rarfile : Infos and docs here : https://pypi.python.org/pypi/rarfile/ https://rarfile.readthedocs.org/en/latest/api

安装yii2-starter-kit

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一.先去github上下下来 https://github.com/yii2-starter-kit/yii2-starter-kit 二.安装，通过composer 如果没安装composer，就先安装composer 三.composer update 无法下载npm-asset/admin-lte等等 nmp下的包查找原因，很可能composer没装这个。 composer global require "fxp/composer-asset-plugin:~1.0.2" 所以装下这个。但是又碰到新问题 Unzip with unzip command failed, falling back to ZipArchive class 大概就是php没装unzip这个扩展所以取安装unzip这个扩展。但是又碰到新问题 system libzip must be upgraded to version >= 0.11 意思，就是系统的libzip版本太低，要安装新的。所以 1.yum -y remove libzip-devel 卸载自带的 2.wget https://libzip.org/download/libzip-1.3.2.tar.gz 下载新的，但是速度真是好慢呀用windows下载，好快。那用ftp上传吧 https://libzip.org

Windows batch script to unzip files in a directory

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问题 I want to unzip all files in a certain directory and preserve the folder names when unzipped. The following batch script doesn't quite do the trick. It just throws a bunch of the files without putting them into a folder and doesn't even finish. What's wrong here? for /F %%I IN ('dir /b /s *.zip') DO ( "C:\Program Files (x86)\7-Zip\7z.exe" x -y -o"%%~dpI" "%%I" ) 回答1: Try this: for /R "C:\root\folder" %%I in ("*.zip") do ( "%ProgramFiles(x86)%\7-Zip\7z.exe" x -y -o"%%~dpI" "%%~fI" ) or (if you

Unzip zip files in folders and subfolders with python

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问题 I try to unzip 150 zip files. All the zip files as different names, and they all spread in one big folder that divided to a lot of sub folders and sub sub folders.i want to extract each archive to separate folder with the same name as the original zip file name and also in the same place as the original zip file . my code is: import zipfile import os,os.path,sys pattern = '*.zip' folder = r"C:\Project\layers" files_process = [] for root,dirs,files in os.walk(r"C:\Project\layers"): for

How to read from a zip file within zip file in Python?

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问题 I have a file that I want to read that is itself zipped within a zip archive. For example, parent.zip contains child.zip, which contains child.txt. I am having trouble reading child.zip. Can anyone correct my code? I assume that I need to create child.zip as a file-like object and then open it with a second instance of zipfile, but being new to python my zipfile.ZipFile(zfile.open(name)) is silly. It raises a zipfile.BadZipfile: "File is not a zip file" on (independently validated) child.zip

unzip a tar.gz file?

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I wish to download and open the following tar.gz file in R: http://s.wordpress.org/resources/survey/wp2011-survey.tar.gz Is there a command which can accomplish this? fn <- "http://s.wordpress.org/resources/survey/wp2011-survey.tar.gz" download.file(fn,destfile="tmp.tar.gz") untar("tmp.tar.gz",list=TRUE) ## check contents untar("tmp.tar.gz") ## or, if you just want to extract the target file: untar("tmp.tar.gz",files="wp2011-survey/anon-data.csv") X <- read.csv("wp2011-survey/anon-data.csv") Offhand, I don't know of a way to reach into the tar file and read the appropriate csv file without

java解压zip rar文件实例

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package com.tservice.mrn.common; import java.io.*; import java.util.Enumeration; import org.apache.tools.ant.Project; import org.apache.tools.ant.taskdefs.Expand; import org.apache.tools.zip.*; import com.github.junrar.Archive; import com.github.junrar.rarfile.FileHeader; public abstract class ZipUtils { private static final int BUFFEREDSIZE = 1024; /** * @SuppressWarnings({ "rawtypes", "resource" }) public static String * unzip(File zipFile, String unzipDir, String * zipFileName) throws IOException { ZipFile zf = new * ZipFile(zipFile); Enumeration enu = zf.entries(); * String result = "";

linux zip/unzip命令详解+实例

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linux zip/unzip命令命令名： zip 功能说明：压缩文件。语　　法：zip [-AcdDfFghjJKlLmoqrSTuvVwXyz$][-b <工作目录>][-ll][-n <字尾字符串>][-t <日期时间>][-<压缩效率>][压缩文件][文件...][-i <范本样式>][-x <范本样式>] 补充说明：zip是个使用广泛的压缩程序，文件经它压缩后会另外产生具有".zip"扩展名的压缩文件。参　　数： -A 调整可执行的自动解压缩文件。 -b<工作目录> 指定暂时存放文件的目录。 -c 替每个被压缩的文件加上注释。 -d 从压缩文件内删除指定的文件。 -D 压缩文件内不建立目录名称。 -f 此参数的效果和指定"-u"参数类似，但不仅更新既有文件，如果某些文件原本不存在于压缩文件内，使用本参数会一并将其加入压缩文件中。 -F 尝试修复已损坏的压缩文件。 -g 将文件压缩后附加在既有的压缩文件之后，而非另行建立新的压缩文件。 -h 在线帮助。 -i<范本样式> 只压缩符合条件的文件。 -j 只保存文件名称及其内容，而不存放任何目录名称。 -J 删除压缩文件前面不必要的数据。 -k 使用MS-DOS兼容格式的文件名称。 -l 压缩文件时，把LF字符置换成LF+CR字符。 -ll 压缩文件时，把LF+CR字

How to zip and unzip the files?

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How to zip and unzip the files which are all already in DDMS : data/data/mypackage/files/ I need a simple example for that. I've already search related to zip and unzip. But, no one example available for me. Can anyone tell some example. Advance Thanks. Take a look at java.util.zip.* classes for zip functionality. I've done some basic zip/unzip code, which I've pasted below. Hope it helps. public static void zip(String[] files, String zipFile) throws IOException { BufferedInputStream origin = null; ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(new FileOutputStream(zipFile)