unzip

I want to unzip all files in a certain directory and preserve the folder names when unzipped. The following batch script doesn't quite do the trick. It just throws a bunch of the files without putting them into a folder and doesn't even finish. What's wrong here? for /F %%I IN ('dir /b /s *.zip') DO ( "C:\Program Files (x86)\7-Zip\7z.exe" x -y -o"%%~dpI" "%%I" ) Try this: for /R "C:\root\folder" %%I in ("*.zip") do ( "%ProgramFiles(x86)%\7-Zip\7z.exe" x -y -o"%%~dpI" "%%~fI" ) or (if you want to extract the files into a folder named after the Zip-file): for /R "C:\root\folder" %%I in ("*.zip")

I have an archive.zip which contains two crypted ".txt" files. I would like to decompress the archive in order to retrieve those 2 files. Here's what I've done so far: FILE *FileIn = fopen("./archive.zip", "rb"); if (FileIn) printf("file opened\n"); else printf("unable to open file\n"); fseek(FileIn, 0, SEEK_END); unsigned long FileInSize = ftell(FileIn); printf("size of input compressed file : %u\n", FileInSize); void *CompDataBuff = malloc(FileInSize); void *UnCompDataBuff = NULL; int fd = open ("archive.zip", O_RDONLY); CompDataBuff = mmap(NULL, FileInSize, PROT_READ | PROT_WRITE, MAP

unzip——命令没有找到，其原因肯定是没有安装unzip。 利用一句命令就可以解决了。 命令是： yum install -y unzip zip 安装成功后就可以使用unzip命令了。 来源： https://my.oschina.net/kuchawyz/blog/3098631

linux zip命令 zip -r myfile.zip ./* 将当前目录下的所有文件和文件夹全部压缩成myfile.zip文件,－r表示递归压缩子目录下所有文件. 2.unzip unzip -o -d /home/sunny myfile.zip 把myfile.zip文件解压到 /home/sunny/ -o:不提示的情况下覆盖文件； -d:-d /home/sunny 指明将文件解压缩到/home/sunny目录下； 3.其他 zip -d myfile.zip smart.txt 删除压缩文件中smart.txt文件 zip -m myfile.zip ./rpm_info.txt 向压缩文件中myfile.zip中添加rpm_info.txt文件 ------------------------------------------------------------------------------- 要使用 zip 来压缩文件，在 shell 提示下键入下面的命令： zip -r filename.zip filesdir 在这个例子里，filename.zip 代表你创建的文件，filesdir 代表你想放置新 zip 文件的目录。-r 选项指定你想递归地（recursively）包括所有包括在 filesdir 目录中的文件。 要抽取 zip 文件的内容

I have a zip file which contains the following directory structure: dir1\dir2\dir3a dir1\dir2\dir3b I'm trying to unzip it and maintain the directory structure however I get the error: IOError: [Errno 2] No such file or directory: 'C:\\\projects\\\testFolder\\\subdir\\\unzip.exe' where testFolder is dir1 above and subdir is dir2. Is there a quick way of unzipping the file and maintaining the directory structure? The extract and extractall methods are great if you're on Python 2.6. I have to use Python 2.5 for now, so I just need to create the directories if they don't exist. You can get a

I receive daily emails where there is an attachment containing 1 zip file containing 1 csv file. In the body of my email, there is an image that is being recognized as another attachment I am pretty sure. The below script works when there is only text in the body of the email but with the "Adobe Marketing Cloud" image, it is screwing up the script. Is there a way I can only read maybe the first attachment read (assuming that will be the zip file)? Here is my script: library(readr) library(RDCOMClient) outlook_app <- COMCreate("Outlook.Application") search <- outlook_app$AdvancedSearch( "Inbox"

I am developing a web page containing Javascript. This js uses static string data (about 1-2 MB) which is stored in a flat file. I could compress it with gzip or any other algorithm to reduce the transfer load. Would it be possible to fetch this binary file with Ajax and decompress it into a string (which I could split later) in the client browser. If yes, how can I achieve this? Does anyone have a code example? And another library or site is this one, although it has few examples it has some thorough test cases that can be seen. https://github.com/imaya/zlib.js Here are some of the complex