unzip

问题 I have access to a remote server over ssh. I have only read (no write) access on the server. There is a zipped log file that I want to read. But because I have only read access, I cannot first extract the file and then read it, because when I try to unzip, I get the message Read-only file system . My idea was to redirect the output of the gunzip -command to some other command that can read from the standrat input and display the content in the console. So I do not write the unzipped file on

问题 Managed to download .zip file to my filesystem on mobile phone. But after a while realised I can't find a way how to unzip that file. As I tried with: https://github.com/plrthink/react-native-zip-archive https://github.com/remobile/react-native-zip First one dies immidiately after requiring, getting error "Cannot read property 'unzip' of undefined" (followed instructions carefully) And the second one dies because it's dependant on codrova port to react native which also doesn't work. Any

问题 I have a number of zipped files say a.zip b.zip etc in a folder. I would like to unzip those and put into a respective directory like a,b .Can you suggest me some unix script for it.? 回答1: Should not be much hard (untested!): #!/bin/bash for zip in *.zip ; do dir=${zip%.zip} mkdir "$dir" unzip -rd "$dir" "$zip" done 回答2: You can use unzip utility in unix, as follows: #!/bin/bash for f in *.zip do echo "unzipping $f" unzip $f -d ${f%.*} done Running this script in directory will unzip all the

问题 I am trying to figure out a way to display the current progress as well as the time remaining to unzip and write the contents of a zip file to disk. I am currently using the ZipArchiver class found here http://code.google.com/p/ziparchive/ which is working quite well. Problem is, that a lot of it is written in C++ which i dont have too much experience in. Here is the relevant function: -(BOOL) UnzipFileTo:(NSString*) path overWrite:(BOOL) overwrite { BOOL success = YES; int ret =

问题 Goal Goal is to make configuration and code readable after it has been exported from an application that stores this data in base64 encoded and gzip-ped format. Test in Linux-shell Example of a string with code "H4sIAAAAAAAAAIWSS0vEMBSF9/0VIYvubHUnNGlhfIDCwOCMuCyhTeOVTBLzGPTfmzY60yKju+Tc8N1z7o2RQYBqmTESuGthaDuHXJpWTRknzsZfowK0DrSi+Ki4x4qrTPShB8fPu/uIaN3VGVsGB4s49BcnrDKGjsJlwaF5P0sMtxY/swLadBeN

问题 I have node app with express and im sending request from client like postman and I need to get the file from the req and extract it on my local folder,how I can do that ? I found the following open source but not sure how to take the req body and extract it in my local folder like "C://Test//extractDest", The code below is taken from the following open source but if there is other good open source for this I can use it instead https://www.npmjs.com/package/decompress-zip var DecompressZip =

问题 I'm first time trying to use GTFS(General Transit Feed Specification) with Google Maps as per the Google developers page i have understood the concept of .txt files which are used as feed and for making a demo i downloaded a transit zip files from Google developers page. but I'm not getting how to use those transit files to show information on map. I tried to search tutorial for the same but could not find anything useful. Do i need to parse all those files to show in map or there is

问题 I searched with Google but I didn't find something for Windows. How can I extract several files into several folders? For example: a.zip , b.zip and c.zip into the folders a , b and c . I am looking for a command prompt command or a batch file solution. Thanks 回答1: With using WinRAR in GUI mode: Start WinRAR . Select all the *.zip files. Click on icon Extract To in toolbar. Enter destination folder or browse to destination folder. Check the option Extract archives to subfolders in group

问题 IMO, I thought that epub is a kind of zip . Thus, I've tried to unzip in a way. public class Main { public static void main(String argv[ ]) { final int BUFFER = 2048; try { BufferedOutputStream dest = null; FileInputStream fis = new FileInputStream("/Users/yelinaung/Documents/unzip/epub/doyle.epub"); ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis)); ZipEntry entry; while ((entry = zis.getNextEntry()) != null) { System.out.println("Extracting: " + entry); int count; byte

问题 I would like just to extract a normal zip file, but it keeps failing. This is my code I'm using now: private File downloadPath = new File(Environment.getExternalStorageDirectory() + "/Test/file.zip"); private File unzipLoc = new File(Environment.getExternalStorageDirectory() + "/Test/"); FileInputStream fin = new FileInputStream(downloadPath); ZipInputStream zin = new ZipInputStream(fin); ZipEntry ze = null; while ((ze = zin.getNextEntry()) != null) { FileOutputStream fout = new