unpivot

I'm dealing with data that has been generated from a survey that has a unique respondant ID as the first column and then has multiple columns relating to the choices of country that the respondent was looking at in relation to finding employees. So my table looks something like: RespondentID Andorra Austria Belgium Cyprus Denmark Finland France 2546078180 Andorra NULL NULL Cyprus NULL NULL NULL 2546077668 NULL NULL Belgium NULL NULL NULL NULL 2546077120 NULL NULL NULL NULL Denmark Finland NULL What I want to end up with is a table that lists the Respondent ID for each answer given. So on the

I want to turn some of the rows into columns while keeping other rows as they are. ID name value RefId 1 Fname John 32145 2 LName Smith 32145 3 Fname Peter 34589 4 LName Mahlang 34589 Now what I want to achieve is to turn the Fname and Lname rows into columns with their matching value field. ID column doesn't really matter, I don't need it. Desired Output Fname Lname RefId John Smith 32145 Peter Mahlang 34589 Any help Using conditional aggregation: select Fname = max(case when name = 'Fname' then value end) , Lname = max(case when name = 'Lname' then value end) , RefId from t group by RefId

I'm trying to pivot a table to get 3 columns my example table is like : CREATE TABLE tbl1 (A1 int, cA1 int,A2 int, cA2 int,A3 int, cA3 int) GO INSERT INTO tbl1 VALUES (60,2,30,3,10,5); GO I am using the query below to get tthe results from two columns: select A, value from tbl1 unpivot ( value for A in ([A1], [A2],[A3]) ) un1; The results are like : A | value --+------- A1|60 A2|30 A3|10 but I want to add and second column with and the results to be like : A | value1 | value2 --+--------+-------- A1| 60 | 2 A2| 30 | 3 A3| 10 | 5 Any Help?? I would use APPLY : select v.* from tbl1 t cross apply