unix

问题 i've got a hundreds of files with thousands of lines, which i need to delete some lines that follows a pattern,so i went to SED with regex .The struct of files is something like this A,12121212121212,foo,bar,lorem C,32JL,JL C,32JL,JL C,32JL,JL C,32JL,JL A,21212121212121,foo,bar,lorem C,32JL,JL C,32JL,JL C,32JL,JL A,9999,88888,77777 I need to delete All the lines that starts with " A " and ends with " lorem " Expected output- C,32JL,JL C,32JL,JL C,32JL,JL C,32JL,JL C,32JL,JL C,32JL,JL C,32JL

问题 i've got a hundreds of files with thousands of lines, which i need to delete some lines that follows a pattern,so i went to SED with regex .The struct of files is something like this A,12121212121212,foo,bar,lorem C,32JL,JL C,32JL,JL C,32JL,JL C,32JL,JL A,21212121212121,foo,bar,lorem C,32JL,JL C,32JL,JL C,32JL,JL A,9999,88888,77777 I need to delete All the lines that starts with " A " and ends with " lorem " Expected output- C,32JL,JL C,32JL,JL C,32JL,JL C,32JL,JL C,32JL,JL C,32JL,JL C,32JL

问题 Basically, so far I have this code: #include <glob.h> #include <string.h> #include <stdio.h> # define ERROR 1 # define FAILURE -1 int main(int ac, char **av) { glob_t globlist; int i; i = 0; if (ac == 1) return (-1); else { if (glob(av[1], GLOB_PERIOD, NULL, &globlist) == GLOB_NOSPACE || glob(av[1], GLOB_PERIOD, NULL, &globlist) == GLOB_NOMATCH) return (FAILURE); if (glob(av[1], GLOB_PERIOD, NULL, &globlist) == GLOB_ABORTED) return (ERROR); while (globlist.gl_pathv[i]) { printf("%s\n",

问题 I need to create a git pull-request from the command line, without installing any wrappers or additional software. Is there any way to do so in git? I can't seem to find any official git documentation which supports this. 回答1: Surprisingly (to a lot of people), pull requests are first-class citizens in the git world and not something invented by GitHub. Use git request-pull to create an E-Mail text you could send over to someone who should fetch some revisions from a server. This server could

问题 I need to create a git pull-request from the command line, without installing any wrappers or additional software. Is there any way to do so in git? I can't seem to find any official git documentation which supports this. 回答1: Surprisingly (to a lot of people), pull requests are first-class citizens in the git world and not something invented by GitHub. Use git request-pull to create an E-Mail text you could send over to someone who should fetch some revisions from a server. This server could

问题 I need to create a git pull-request from the command line, without installing any wrappers or additional software. Is there any way to do so in git? I can't seem to find any official git documentation which supports this. 回答1: Surprisingly (to a lot of people), pull requests are first-class citizens in the git world and not something invented by GitHub. Use git request-pull to create an E-Mail text you could send over to someone who should fetch some revisions from a server. This server could

问题 I need to create a git pull-request from the command line, without installing any wrappers or additional software. Is there any way to do so in git? I can't seem to find any official git documentation which supports this. 回答1: Surprisingly (to a lot of people), pull requests are first-class citizens in the git world and not something invented by GitHub. Use git request-pull to create an E-Mail text you could send over to someone who should fetch some revisions from a server. This server could

问题 What is the design rationale that cat doesn't take list of file names from pipe input? Why did the designers choose that the following does not work? ls *.txt | cat Instead of this, they chose that we need to pass the file names as argument to cat as: ls *.txt | xargs cat 回答1: When you say ls *.txt | cat doesn't work, you should say that doesn't work as you expect. In fact, that works in the way it was thought to work. From man : cat - Concatenate FILE(s), or standard input, to standard

问题 What is the design rationale that cat doesn't take list of file names from pipe input? Why did the designers choose that the following does not work? ls *.txt | cat Instead of this, they chose that we need to pass the file names as argument to cat as: ls *.txt | xargs cat 回答1: When you say ls *.txt | cat doesn't work, you should say that doesn't work as you expect. In fact, that works in the way it was thought to work. From man : cat - Concatenate FILE(s), or standard input, to standard

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 8 years ago . Improve this question am very much interested in unix. Want to learn in and out. Can you guys help me by listing some books which can make me a wizard? Ultimately I want to become a unix programmer. I am not a novice user in Unix. 回答1: You want system administration knowledge, or programming knowledge? For