Unix time and leap seconds
Regarding Unix (POSIX) time, Wikipedia says: Due to its handling of leap seconds, it is neither a linear representation of time nor a true representation of UTC. But the Unix date command does not seem to be aware of them actually $ date -d '@867715199' --utc Mon Jun 30 23:59:59 UTC 1997 $ date -d '@867715200' --utc Tue Jul 1 00:00:00 UTC 1997 While there should be a leap second there at Mon Jun 30 23:59:60 UTC 1997 . Does this mean that only the date command ignores leap seconds, while the concept of Unix time doesn't? Thomas Jung The number of seconds per day are fixed with Unix timestamps .