unix-timestamp

Hello I have and SLQLite database in which I have table water_logs CREATE TABLE water_logs( _id INTEGER PRIMARY KEY AUTOINCREMENT, amount REAL NOT NULL, icon INTEGER NOT NULL, date INTEGER NOT NULL); I store date in milliseconds. Calendar cal = Calendar.getInstance(); cal.getTimeInMillis(); My problem is I want to get the day from the my date column using strftime function. The problem is tjat java calendar timestamp is different from SLQLite time stamp 1436859563832 --> result from cal.getTimeInMillis(); 1436607407--> SELECT strftime('%s','now') What I'm actually trying to do is to group

I know something like this can be accomplished easily using PHP or Perl, but I want to know if there's a way to do it directly on Informix, something like the function FROM_UNIXTIME() on MySQL. I think you can do it using dbinfo with 'utc_to_datetime' as a parameter: http://publib.boulder.ibm.com/infocenter/idshelp/v115/index.jsp?topic=%2Fcom.ibm.sqls.doc%2Fids_sqs_1484.htm 来源： https://stackoverflow.com/questions/9213273/is-there-a-direct-way-to-convert-unix-time-on-informix-to-yyyy-mm-dd-hhmmss

I have a 32 bit Linux system in which I have to record data that is timestamped with a UINT32 second offset from an epoch of 1901-01-01 00:00:00. Calculating the timestamp is ok for me as I can use the 64 bit ticks() counter and ticks_per_second() functions to generate the seconds since epoch as follows (I only require second level resolution) const ptime ptime_origin(time_from_string("1901-01-01 00:00:00")); time_duration my_utc = microsec_clock::universal_time() - ptime_origin; boost::int64_t tick_per_sec = my_utc.ticks_per_second(); boost::int64_t tick_count = my_utc.ticks(); boost::int64_t

mysql> SELECT FROM_UNIXTIME(2145916799), FROM_UNIXTIME(2145916800), POW(2,32-1)-1, 2145916799 - POW(2,32-1)-1; +---------------------------+---------------------------+---------------+----------------------------+ | FROM_UNIXTIME(2145916799) | FROM_UNIXTIME(2145916800) | POW(2,32-1)-1 | 2145916799 - POW(2,32-1)-1 | +---------------------------+---------------------------+---------------+----------------------------+ | 2037-12-31 18:59:59 | NULL | 2147483647 | -1566850 | +---------------------------+---------------------------+---------------+----------------------------+ 1 row in set (0.00 sec

How can i calculate day number from a unix-timestamp, in a mathematical way and without using any functions and in simple math formula. 1313905026 --> 8 (Today 08/21/2011) JSideris There is no simple formula to do this. You would need to subtract the number of years (accounting for leap years) since the epoch, which would probably require a loop or a discrete calculation of some kind. Then use some type of loop to subtract out the number of seconds in each month for the current year. What you are left with is the number of seconds currently into the month. I would do something like this. x = .

I need to convert double with number of seconds since the epoch to ptime . I'm prety sure there must be an easy way to do this, but I couldn't find anything. Thanks. Edit: The original timestamp is floating point. I can't change it and i don't want to lose the sub-second precision. Use the from_time_t() conversion function. A time_t is a UNIX timestamp, i.e. the number of seconds since the epoch. For a machine that has boost date/time compiled to the default level of microsecond resolution, try this: double ts = 1250524800.5; // Use floor() here if seconds are always positive. time_t