unique

问题 I have a problem in R, which I can't seem to solve. I have the following dataframe: Image 1 I would like to: Find the unique combinations of the columns 'Species' and 'Effects' Report the concentration belonging to this unique combination If this unique combination is present more than one time, calculate the mean concentration And would like to get the following dataframe: Image 2 I have tried next script to get the unique combinations: UniqueCombinations <- Data[!duplicated(Data[,1:2]),]

问题 the three lines of R code below show a vector a1,b1 and "c1" which is the unique of fields a1. I want to display a data frame of two columns where I should get every element of c1 displayed the number of times equal to the length of elements in "a1", in one column, and the corresponding ID "b1" of that letter in another column. Simply, say a data frame with column "y" in which say letter "a" from "c1" will be represented 6 times back to back(length of string a1), then "b" 6 times, then c and

问题 I am trying to have this rules in my model 'Email' => 'email|unique:tablename,coloumntoignore,ignoreid', The above rules is to check the unique coloumn except the id to be supplied in the ignoreid I face two issues here I am getting the user input $DriverData = Input::except(array('_token')); and sending it to the model $validation = Validator::make($DriverData, DriverModel::$updaterules); Note : This update is not the self so i can't get it by Auth::user()->id and my primary key is not id I

问题 I have a vector fruit with three entries Peach, Plum, Pear . I would like to find each unique pairing in fruit and create a new, two column data.frame (e.g. df.new below). How might I do this in r for an even larger data.set? expand.grid results in pear-plum and plum-pear which are not unique pairings, or not the ones I am seeking. Any suggestions? fruit <- c("Peach", "Plum", "Pear") fruit1 <- c("Peach", "Peach", "Plum") fruit2 <- c("Plum", "Pear", "Pear") df.new <- data.frame(fruit1, fruit2)

问题 I have a table of 'words', and what I want to do is, if a user uses that word, insert it into the table. But, if it already exists, update the count on that word. I don't see a way to actually set columns as unique.. That said, how do I avoid the race condition: t1 - user1 checks if 'Love' is used. NO t2 - user2 checks if 'Love' is used. NO t3 - user1 adds 'Love' t4 - user2 adds 'Love' I do not want this to be in the database twice. Anyway to accomplish this in Parse? 回答1: You can use the

问题 I want to read a column in Excel worksheet using SpreadSheetGear (.NET) and get unique values in that column back. Example: From the above Excel worksheet, I need to read column B and get back unique values "John" "Mike" and "Wayne" In real life, there can be 1,000,000+ rows so efficiency is important. How is that achieved? 回答1: I Understand that the post is quite old but could be helpful for others: The comment entered by @Michael Moreno will be helpful and I endorse the idea. But the

问题 I want to generate random unique int numbers from an interval but the app freezes out (infinite loop). int[] ids = new int[200]; for(int i = 0; i < ids.length; i++){ int temp = getUnique(ids); ids[i] = temp; } private int getUnique(int[] ids){ while(true){ int iRand = random(0, ids.length); if( unique( ids, iRand ) ) return iRand; } } private boolean unique(int[] arr, int i){ for(int k : arr){ if(k == i) return false; } return true; } private int random(int Min, int Max){ return Min + (int)

问题 I have a data frame that looks like this: date time id datetime 1 2015-01-02 14:27:22.130 999000000007628 2015-01-02 14:27:22 2 2015-01-02 14:41:27.720 989001002807730 2015-01-02 14:41:27 3 2015-01-02 14:41:27.940 989001002807730 2015-01-02 14:41:27 4 2015-01-02 14:41:28.140 989001002807730 2015-01-02 14:41:28 5 2015-01-02 14:41:28.170 989001002807730 2015-01-02 14:41:28 6 2015-01-02 14:41:28.350 989001002807730 2015-01-02 14:41:28 I need to find the number of unique "id"s for each "date" in

问题 Is there any other way of getting a list of all unique characters in a textfile? I've tried the following way but is there a more pythonic way? Can the same output be achieved in unix command? >>> import codecs >>> from collections import Counter >>> with codecs.open('my.txt','r','utf8') as fin: ... x = Counter(fin.read()) ... print [i for i in x if len(i) == 1] ... [u'\u2014', u'\u2018', u'\u201c', u' ', u'\xa3', u'$', u'(', u',', u'0', u'4', u'8', u'@', u'D', u'H', u'L', u'P', u'T', u'\xd7'

问题 I've tried a number of methods to filter a column for unique values (including blanks and blanks with a space inside). I want to filter these values and then paste them into column a in another sheet. Sub filter_2() With Sheets("ICM flags") .Columns("a").AdvancedFilter Action:=xlFilterCopy, copytorange:=Sheets("Flag Update (2)").Range("a2"), Unique:=True End With End Sub The method above works for .range("a2") but if I try to use .range("a1") I get runtime error 1004 advanced filter method of