unicode

Convert fancy/artistic unicode text to ASCII

放肆的年华 提交于 2021-01-19 08:53:37
问题 I have a unicode string like "𝖙𝖍𝖚𝖌 𝖑𝖎𝖋𝖊" and would like to convert it to the ASCII form "thug life". I know I can achieve this in Python by import unidecode print(unidecode.unidecode('𝖙𝖍𝖚𝖌 𝖑𝖎𝖋𝖊')) // thug life However, this would asciify also other unicode characters (such as Chinese/Japanese characters, emojis, accented characters, etc.), which I want to preserve. Is there a way to detect these type of "artistic" unicode characters? Some more examples: 𝓽𝓱𝓾𝓰 𝓵𝓲𝓯𝓮 𝓉𝒽𝓊𝑔 𝓁𝒾𝒻𝑒 𝕥𝕙𝕦𝕘 𝕝𝕚𝕗𝕖 thug life

Why is the same character compared twice by changing its case to UPPER and then to lower?

爷,独闯天下 提交于 2021-01-19 03:20:26
问题 The below code is in Class String in java. I don't understand why the characters from two different strings are compared twice . at first by doing upper case and if that fails by doing lower case. My Question here is, is it required? If yes, why? public static final Comparator<String> CASE_INSENSITIVE_ORDER = new CaseInsensitiveComparator(); private static class CaseInsensitiveComparator implements Comparator<String>, java.io.Serializable { // use serialVersionUID from JDK 1.2.2 for

Why is the same character compared twice by changing its case to UPPER and then to lower?

眉间皱痕 提交于 2021-01-19 03:15:28
问题 The below code is in Class String in java. I don't understand why the characters from two different strings are compared twice . at first by doing upper case and if that fails by doing lower case. My Question here is, is it required? If yes, why? public static final Comparator<String> CASE_INSENSITIVE_ORDER = new CaseInsensitiveComparator(); private static class CaseInsensitiveComparator implements Comparator<String>, java.io.Serializable { // use serialVersionUID from JDK 1.2.2 for

Why is the same character compared twice by changing its case to UPPER and then to lower?

人走茶凉 提交于 2021-01-19 03:14:02
问题 The below code is in Class String in java. I don't understand why the characters from two different strings are compared twice . at first by doing upper case and if that fails by doing lower case. My Question here is, is it required? If yes, why? public static final Comparator<String> CASE_INSENSITIVE_ORDER = new CaseInsensitiveComparator(); private static class CaseInsensitiveComparator implements Comparator<String>, java.io.Serializable { // use serialVersionUID from JDK 1.2.2 for

complete, monospaced Unicode font? [closed]

帅比萌擦擦* 提交于 2021-01-10 03:47:52
问题 Closed. This question is off-topic. It is not currently accepting answers. Closed 9 years ago . Locked . This question and its answers are locked because the question is off-topic but has historical significance. It is not currently accepting new answers or interactions. I'm looking for a good programming font that lets me add comments and string literals in Unicode, usually Japanese and Chinese along with some Latin and Cyrillic languages. So far the situation seems to be "complete,

complete, monospaced Unicode font? [closed]

断了今生、忘了曾经 提交于 2021-01-10 03:39:47
问题 Closed. This question is off-topic. It is not currently accepting answers. Closed 9 years ago . Locked . This question and its answers are locked because the question is off-topic but has historical significance. It is not currently accepting new answers or interactions. I'm looking for a good programming font that lets me add comments and string literals in Unicode, usually Japanese and Chinese along with some Latin and Cyrillic languages. So far the situation seems to be "complete,

How to correctly count æ ø å (Unicode as UTF-8) characters in C?

我只是一个虾纸丫 提交于 2021-01-06 09:34:48
问题 I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this? int length() { pointer = root; // Reset pointer int i; // Looping through data in node int len = 0; // Counting characters int sizedata = sizeof(pointer->data); // Sets size limit for data in

How to correctly count æ ø å (Unicode as UTF-8) characters in C?

徘徊边缘 提交于 2021-01-06 09:30:18
问题 I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this? int length() { pointer = root; // Reset pointer int i; // Looping through data in node int len = 0; // Counting characters int sizedata = sizeof(pointer->data); // Sets size limit for data in

How to correctly count æ ø å (Unicode as UTF-8) characters in C?

℡╲_俬逩灬. 提交于 2021-01-06 09:30:18
问题 I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this? int length() { pointer = root; // Reset pointer int i; // Looping through data in node int len = 0; // Counting characters int sizedata = sizeof(pointer->data); // Sets size limit for data in

How to correctly count æ ø å (Unicode as UTF-8) characters in C?

谁说我不能喝 提交于 2021-01-06 09:29:44
问题 I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this? int length() { pointer = root; // Reset pointer int i; // Looping through data in node int len = 0; // Counting characters int sizedata = sizeof(pointer->data); // Sets size limit for data in