Map an array of arrays
来源： https://stackoverflow.com/questions/35325767/map-an-array-of-arrays
underscore.js
JavaScript - merge two arrays of objects and de-duplicate based on property value
来源： https://stackoverflow.com/questions/37057746/javascript-merge-two-arrays-of-objects-and-de-duplicate-based-on-property-valu
do <something> N times (declarative syntax)
来源： https://stackoverflow.com/questions/10993824/do-something-n-times-declarative-syntax
Underscore equivalent of Lodash _.get and _.has
问题 I am trying to have search for Underscore equivalent for Lodash _.get and _.has , where it is able to directly access the existence and value of nested object value without the need of checking the existence of its parents. However, it seems to me that underscore _.get and _.has only able to check the value for the first level. var object = { 'a': { 'b': 2 } }; _.has(object, 'a.b'); // lodash shows true _.has(object, 'a.b'); // underscore shows false 回答1: As far as I know, undercore doesn't
setTimeout and array each
问题 I'm confused with using setTimeout and the each iterator. How can I rewrite the following so that the console outputs each name after a delay of 5 seconds? Currently the code below prints all the names at once after 5 seconds. I would like to: 1) wait 5 seconds, then print kevin 2) wait 5 seconds, then print mike 3) wait 5 seconds, then print sally var ary = ['kevin', 'mike', 'sally']; _(ary).each(function(person){ setTimeout(function(){ console.log(person); }, 5000); }); 回答1: You could
lodash和下划线之间的差异[关闭]
问题： Why would someone prefer either the lodash.js or underscore.js utility library over the other? 为什么有人更喜欢 lodash.js 或 underscore.js 实用程序库而不是另一个？ Lodash seems to be a drop-in replacement for underscore, the latter having been around longer. Lodash似乎是下划线的替代品，后者已经存在了更长时间。 I think both are brilliant, but I do not know enough about how they work to make an educated comparison, and I would like to know more about the differences. 我认为两者都很精彩，但我对他们如何努力进行有根据的比较并不了解，我想更多地了解这些差异。 解决方案： 参考一： https://stackoom.com/question/vrJC/lodash和下划线之间的差异-关闭 参考二： https://oldbug.net/q/vrJC/Differences-between-lodash
JAXB attributes using underscore
问题 I working on JAXB to using java object I am creating xml.But im using javaclass fields Like qpack_id as attrubute it creating in xml file like qpackId so how can i use _(underscore) in jaxB please guide me. xml file should create bellow attibute <qpack " qpack_id="MB0046_SET4" qpack_name="MB0046"> </qpack> 回答1: Starting from Java Classes You can use the XmlAttribute annotation to specify a name. @XmlAttribute(name="qpack_name") public String getQPackName() { return qPackName; } Starting from
Merge two objects and overwrite the values if conflict
问题 I'm trying to merge two objects and overwrite the values in the process. Is it possible with underscore to do the following? (I'm fine with not using underscore I just want it to be simple) var obj1 = { "hello":"xxx" "win":"xxx" }; var obj2 = { "hello":"zzz" }; var obj3 = merge(obj1, obj2); /* { "hello":"zzz", "win":"xxx" } */ 回答1: Use extend: var obj3 = _.extend({}, obj1, obj2); The first argument is modified, so if you don't want to modify obj1 or obj2 just pass in {} . 回答2: in ES6 or
Merge two objects and overwrite the values if conflict
问题 I'm trying to merge two objects and overwrite the values in the process. Is it possible with underscore to do the following? (I'm fine with not using underscore I just want it to be simple) var obj1 = { "hello":"xxx" "win":"xxx" }; var obj2 = { "hello":"zzz" }; var obj3 = merge(obj1, obj2); /* { "hello":"zzz", "win":"xxx" } */ 回答1: Use extend: var obj3 = _.extend({}, obj1, obj2); The first argument is modified, so if you don't want to modify obj1 or obj2 just pass in {} . 回答2: in ES6 or
Group Array with count
问题 I have an array of items that contains several properties. One of the properties is an array of tags. What is the best way of getting all the tags used in those items and ordered by the number of times that those tags are being used on those items? I've been trying to look to underscore js but not getting the expected results. return _.groupBy(items, 'tags'); Example of my data: item1 - itemName: item1 - tags(array): tag1, tag2 item2 - itemName: item2 - tags(array): tag1, tag3 so I'm trying