typing

python typing module missing the Coroutine class in python 3.5

自古美人都是妖i 提交于 2019-12-09 15:36:35
问题 I am trying to write code which uses the Coroutine class, as described in the typing documentation. It's look like it's available in python 3.5 , but when I am typing to import it throws me an ImportError : In [1]: from typing import Coroutine ImportError: cannot import name 'Coroutine' Then, I tried to run the code in Python 3.6 and it worked fine. Does this class not available in python 3.5 ? If not, why it's appear in the documentation (of python 3.5 in particular)? I tried to run it with

Python type annotations for Enum value

柔情痞子 提交于 2019-12-09 08:23:35
问题 I have this piece of code: import enum class Color(enum.Enum): RED = '1' BLUE = '2' GREEN = '3' def get_color_return_something(some_color): pass How do I properly add type annotations to the some_color varaible in this function, if I suppose to receive a value from the Color enum (for example: Color.RED )? 回答1: Type hinting the Color class should work: def get_color_return_something(some_color: Color): print(some_color.value) 回答2: def get_color_return_something(some_color: Color): pass 来源:

Typing problems in PyCharm

喜你入骨 提交于 2019-12-08 14:19:42
问题 I have the following function: def clock(dimS: Tuple[int] =(0)) -> Generator[Tuple[int], None, None]: """ Produce coordinates """ itr = 0 dim = len(dimS) maxItr = np.prod(dimS) if (dim < 1): raise ValueError( 'function clock expected positive number of dimensions, received: 0' ) while itr < maxItr: c = [] ind = itr # build coordinate for i in range(dim): s = dimS[dim - i - 1] g = ind % s ind //= s # update c.append(g) itr += 1 yield tuple(reversed(c)) I'm using PyCharm to edit my code (love

Return type 'never' if an optional parameter is given to be a specific value

懵懂的女人 提交于 2019-12-08 07:53:36
问题 I have a function that takes an optional boolean argument that defaults to false . When the argument is false , the function returns a string . When the argument is true , the function should return type never . Here's what I tried: function example(arg: true): never; function example(arg = false): string { //... } This feels like it should work: arg is inferred to have a boolean type, and when it is not passed or passed as false , example returns string . When it is passed as true , the

How to use np.empty inside numba compiled function; Error message “All templates rejected”

让人想犯罪 __ 提交于 2019-12-08 05:52:34
问题 I ran into this weird error when trying to use np.empty in a function definition compiled with numba, and turning on nopython=True to make sure optimized typing is in effect. It's weird because numba claims to support np.empty with the first two arguments, and I am only using the first two arguments (correctly I think?), so I don't know why it's not typing correctly. @jit(nopython=True) def empty(): return np.empty(5, np.float) After defining the above function in an ipython notebook, empty()

“virtual” method's return type in objective-c

我们两清 提交于 2019-12-08 01:16:05
问题 I have a class which is supposed to be abstract. In one of it's abstract methods the return type may be an instance of class1,class2 or class3, depending on the class that's implementing the method. I'm wondering how should I declare the method in the abstract class. I thought about using dynamic typing, but I want the return type to be restricted to one of the 3 classes, not every type, and in addition I'm not sure I can override it so that in the inheriting class the return type will not

How to use np.empty inside numba compiled function; Error message “All templates rejected”

对着背影说爱祢 提交于 2019-12-07 13:36:28
I ran into this weird error when trying to use np.empty in a function definition compiled with numba, and turning on nopython=True to make sure optimized typing is in effect. It's weird because numba claims to support np.empty with the first two arguments, and I am only using the first two arguments (correctly I think?), so I don't know why it's not typing correctly. @jit(nopython=True) def empty(): return np.empty(5, np.float) After defining the above function in an ipython notebook, empty() Gives the following error message: -------------------------------------------------------------------

Knowing if a Scala object is an instance of Case Class

不羁岁月 提交于 2019-12-07 10:18:43
问题 I was wondering if there as a way to know if an object is an instance of a case class. I was trying to find some structural type matching unapply , I notice they inherit Product . My real need for a function that would go something like: def withCaseClass[T <: /* matcher for case class */](obj:T) ... My major interest is to make sure only case classes can be passed to this function. 回答1: A case class is an implementation detail. One can create a class that acts exactly like a case class --

What are the conventions for types in Ruby?

大兔子大兔子 提交于 2019-12-07 08:55:13
问题 Being that Ruby is a language with purely dynamic types, I'm never quite sure what level of expectation I should have for the types passed to my methods. For example, if my method only functions when passed an Integer, should I be actively checking to make sure that's the case or should I just allow a type exception in such a case? Additionally, when it comes to writing design documents around Ruby code, what would be the proper way to specify what types a method should operate on? Javadocs

Return type 'never' if an optional parameter is given to be a specific value

折月煮酒 提交于 2019-12-07 08:44:28
I have a function that takes an optional boolean argument that defaults to false . When the argument is false , the function returns a string . When the argument is true , the function should return type never . Here's what I tried: function example(arg: true): never; function example(arg = false): string { //... } This feels like it should work: arg is inferred to have a boolean type, and when it is not passed or passed as false , example returns string . When it is passed as true , the overload kicks in and example returns never . However, this doesn't work at all. TypeScript gives arg the