tuples

Does type order in std::tuple arguments have any effects?

喜你入骨 提交于 2019-12-08 15:22:59
问题 Say I want to store three types in a tuple : int , float and std::vector<double> If I leave aside matters of subsequent interface, does this tuple<int, float, vector<int>> t; have any differences from this tuple<vector<int>, int, float> t; Due to the implementation of tuple as a class of variadic bases, I'm expecting a different layout for the produced classes, but does it matter in any way ? Also are there any optimization considerations to take into account, when placing types in a tuple

Generate a list of random weighted tuples from a list

萝らか妹 提交于 2019-12-08 15:07:32
问题 Given a tuple list a : a =[(23, 11), (10, 16), (13, 11), (12, 3), (4, 15), (10, 16), (10, 16)] We can count how many appearances of each tuple we have using Counter : >>> from collections import Counter >>> b = Counter(a) >>> b Counter({(4, 15): 1, (10, 16): 3, (12, 3): 1, (13, 11): 1, (23, 11): 1} Now, the idea is to select 3 random tuples from the list, without repetition , such that the count determines the probability that a particular tuple is chosen. For instance, (10, 16) is more

Convert a RDD of Tuples of Varying Sizes to a DataFrame in Spark

佐手、 提交于 2019-12-08 13:43:23
问题 I am having difficulty in converting an RDD of the follwing structure to a dataframe in spark using python. df1=[['usr1',('itm1',2),('itm3',3)], ['usr2',('itm2',3), ('itm3',5),(itm22,6)]] After converting, my dataframe should look like the following: usr1 usr2 itm1 2.0 NaN itm2 NaN 3.0 itm22 NaN 6.0 itm3 3.0 5.0 I was initially thinking of coverting the above RDD structure to the following: df1={'usr1': {'itm1': 2, 'itm3': 3}, 'usr2': {'itm2': 3, 'itm3': 5, 'itm22':6}} Then use python's

pandas how to convert a dataframe into a dictionary of tuples tuple using 1 col as key and the rest as a tuple of form (col2:col3)

試著忘記壹切 提交于 2019-12-08 12:45:59
问题 I am trying to figure out the best way of creating tuples with the format: (x:y) from 2 columns in a dataframe and then use column a of the dataframe as the key of the tuple key data_1 data_2 0 14303 24.75 25.03 1 12009 25.00 25.07 2 14303 24.99 25.15 3 12009 24.62 24.77 The resulting dictionary {14303 24.38:24.61 24:99:25:15 12009 24.62:24.77 25.00:25.07 } I have tried to use iterrows and enumerate but was wondering if there is a more efficient way to achieve it 回答1: I think you wanted to

Removing duplicates members from a list of tuples

我怕爱的太早我们不能终老 提交于 2019-12-08 11:27:59
问题 this question might have similars in SO but my case is a bit different. and I tried to adapt those answers to my problem but couldn't. so here is the thing: I have this list : [(['c', 'a', 'b'], 10), (['c', 'a', 'b'], 9),(['h','b'],2)] for example. I want to remove the duplicates in this list by keeping tuple that has the larger number associated with it. so the list should look like this: [(['c', 'a', 'b'], 10),(['h','b'],2)] can anyone help me? the order of the items inside the inner lists

c# LINQ query filling a Tuple List

走远了吗. 提交于 2019-12-08 11:21:10
问题 I need to fill a Tuple-List with values from a MSSQL-Database with help of Linq to Entities. The code snippet below will help to get a Tuple-List where 1 Database row reflects 1 Tuple Entry. In case there are 3 rows for calculateData we would get 3 Tuple Entries in that list created with Field1 to Field4 . The code below makes it possible: var queryResult = (from a in calculate join b in calculateData on a.Id equals b.CalcId into c where a.SpecialID == 2023 && a.VersionId == 1 orderby a

Attempting to generate Pascal's Triangle as a tuple using recursion

怎甘沉沦 提交于 2019-12-08 11:17:22
问题 I need to write a function to generate Pascal's Triangle as a tuple using recursion. e.g pascal(5) ((1,), (1, 1), (1, 2, 1), (1, 3, 3, 1), (1, 4, 6, 4, 1)) I can generate it as a list with the following function: def triangle(n): if n == 0: return [] elif n == 1: return [[1]] else: new_row = [1] result = triangle(n-1) last_row = result[-1] for i in range(len(last_row)-1): new_row.append(last_row[i] + last_row[i+1]) new_row += [1] result.append(new_row) return result And I've tried changing

Scala: mutable HashMap does not update inside for loop

感情迁移 提交于 2019-12-08 10:23:29
问题 I have a var permutedTables = HashMap[List[Int], List[String, String]] defined globally. I first populate the Hashmap with the keys in a method, which works. print(permutedTables) : Map(List(1,2,3,4) -> List(), List(2,4,5,6) -> List(), etc...) The problem occurs when I want to update the values (empty lists) of the HashMap inside a for loop (inside a second method). In other words, I want to add tuples (String, String) in the List() for each key. for(pi_k <- permutedTables.keySet){ var mask =

Identically sorting two lists

僤鯓⒐⒋嵵緔 提交于 2019-12-08 09:37:41
问题 I have on list of strings, and one list of integers. They come in "pairs", i.e. at an index, the given string and integer must still be "matched up". I need to sort the integers in descending order and have the strings sort identically, so the pairs are intact. I imagine the best way to achieve may be to just put them into List>, but I'm not sure how that could be sorted by the second Tuple item. 回答1: If you have a list of Tuples you could order them like this myList.OrderBy(x => x.Item2);

How to sort similar values in a sorted list (based on second value) of tuples based on another value(third value) in the tuple in descending order

隐身守侯 提交于 2019-12-08 09:03:22
问题 I have a list of tuples of the format [("d",21,5),(e,21,4),("a",20,1),("b",20,3),("c",20,2),...] where the first values (a,b,c etc) are unique and the other two values in tuple might repeat.(like 20) I want to sort the list based on 2nd element(here 20,21) in tuple in ascending order, like [a,b,c,d,e] Then i want the values sorted based on same numbers like (a,b,c) where sorted based on 20 and (d,e) based on 21 to be sorted based on 3rd value(here 1,2,3,4,5) of tuple in descending order, like