tuples

问题 I have two multi-index dataframes: mean and std arrays = [['A', 'A', 'B', 'B'], ['Z', 'Y', 'X', 'W']] mean=pd.DataFrame(data={0.0:[np.nan,2.0,3.0,4.0], 60.0: [5.0,np.nan,7.0,8.0], 120.0:[9.0,10.0,np.nan,12.0]}, index=pd.MultiIndex.from_arrays(arrays, names=('id', 'comp'))) mean.columns.name='Times' std=pd.DataFrame(data={0.0:[10.0,10.0,10.0,10.0], 60.0: [10.0,10.0,10.0,10.0], 120.0:[10.0,10.0,10.0,10.0]}, index=pd.MultiIndex.from_arrays(arrays, names=('id', 'comp'))) std.columns.name='Times'

问题 i was wondering if there was any simple way around sorting tuples in lists in python, for instance if i have a list: list01 = ([a,b,c],[b,a,d],[d,e,c],[a,f,d]) and i sorted it, i would get: ([a,b,c],[a,b,d],[c,d,e],[a,d,f])? or even: ([a,b,c],[a,b,d],[a,d,f],[c,d,e]) if that's easier Thanx in advance:) 回答1: >>> list01 = (['a','b','c'],['b','a','d'],['d','e','c'],['a','f','d']) >>> map(sorted, list01) [['a', 'b', 'c'], ['a', 'b', 'd'], ['c', 'd', 'e'], ['a', 'd', 'f']] >>> sorted(map(sorted,

问题 I'm looking at the Condvar example and am curious how the tuples pair and pair2 are destructured: let pair = Arc::new((Mutex::new(false), Condvar::new())); let pair2 = pair.clone(); // ... thread::spawn(move|| { let &(ref lock, ref cvar) = &*pair2; // ... } Removing the & from pair2 : let &(ref lock, ref cvar) = *pair2; gives a compiler error as I expected: 11 | let &(ref lock, ref cvar) = *pair2; | ^^^^^^^^^^^^^^^^^^^^^ expected tuple, found reference | = note: expected type `(std::sync:

问题 Related, but not Duplicate (it's a completely different language, PHP not C#): How to create multi-dimensional array from a list? How would I go about converting a list of 'Tuple's to string[,]? This is part of a web crawler, but i'm messing with conversions of lists and arrays just out of curiosity. Here's the method. private string[,] getimages(string url) { List<Tuple<string, string>> images = new List<Tuple<string, string>>(); string raw = client.DownloadString(url); while (raw.Contains("

问题 Scala REPL gives the same type for both expressions - (tuple? -- strange!). Yet ("a" ->1) which is a Map I can add to map and ("a", 1) can not. Why Scala REPL shows tuple type type for Map expression? scala> :t ("a" -> 1) (String, Int) scala> :t ("a",1) (String, Int) scala> val m = Map.empty[String, Int] m: scala.collection.immutable.Map[String,Int] = Map() scala> m + ("a",1) <console>:9: error: type mismatch; found : String("a") required: (String, ?) m + ("a",1) ^ scala> m + ("a" ->1) res19:

问题 The following class parses through a very large string (an entire novel of text) and breaks it into consecutive 4-character strings that are stored as a Tuple. Then each tuple can be assigned a probability based on a calculation. I am using this as part of a monte carlo/ genetic algorithm to train the program to recognize a language based on syntax only (just the character transitions). I am wondering if there is a faster way of doing this. It takes about 400ms to look up the probability of

问题 Given a table of revenue values thus: A key point to note (and the core of my question) is the the brand name will almost always, but not always, contain the corresponding product name. In the case of last Banana entry, it doesn't. I will extract a dict of Brand<->Revenue pairs, fist accounting for those brands that have multiple entries, and summing in those cases, using the approach described here. So: revenuePerBrandDict = {} brandRevenueTuples = [] i=0 for brand in ourTab.columns[1][1:-1]

问题 One way to make a numpy array hashable is setting it to read-only. This has worked for me in the past. But when I use such a numpy array in a tuple, the whole tuple is no longer hashable, which I do not understand. Here is the sample code I put together to illustrate the problem: import numpy as np npArray = np.ones((1,1)) npArray.flags.writeable = False print(npArray.flags.writeable) keySet = (0, npArray) print(keySet[1].flags.writeable) myDict = {keySet : 1} First I create a simple numpy

问题 The following piece of code attempts to create a map that shows the minimum number of moves it would take to get from each square on that map to the specified location. The function as a whole is largely irrelevant to the problem, but I thought I should provide my problem in context. I've also imported deque from collections. The strange part comes in at line 7. I get TypeError: 'int' object not iterable. But the statement "distance_from_loc, f_loc = squares_to_check.popleft()" shouldn't be

问题 I know how to extract associated values in enum cases using switch statement: enum Barcode { case upc(Int, Int, Int, Int) case quCode(String) } var productBarcode = Barcode.upc(8, 10, 15, 2) switch productBarcode { case let .upc(one, two, three, four): print("upc: \(one, two, three, four)") case .quCode(let productCode): print("quCode \(productCode)") } But I was wondering if there is a way to extract associated value using tuples. I tried let (first, second, third, fourth) = productBarcode