tuples

问题 I have a dictionary looking like this: dict1 = {'key1': ['x1', [(time1,value1), (time3,value3), (time2,value2)]], 'key2': ['x2', [(time6,value6), (time4,value4), (time5,value5)]], ...} For each key in the dictionary, I wish to sort the tuples based on the time. Looking at the example above, assume that time1 < time2 < time3 time4 < time5 < time6 The output I wish is then dict1 = {'key1': ['x1', [(time1,value1), (time2,value2), (time3,value3)]], 'key2': ['x2', [(time4,value4), (time5,value5),

问题 I am a beginner in python and desperately need someone's help. I am trying to convert a text into tuples in a list. The original text was already tokenized and each pos was tagged as below: The/DT Fulton/NNP County/NNP Grand/NNP Jury/NNP said/VBD Friday/NNP an/DT And the desired output looks as below: [('The', 'DT'), ('Fulton', 'NNP'), ('County', 'NNP'), ...)] So, if anyone can offer me a help, it would be so awesome! Thanks in advance! 回答1: You can use list comprehension like below: >>> s =

问题 Here is a program where each line was split into pairs using tuples, such that every alphabet had a corresponding numeric as A:6, B:6, C:35 ..etc If a value for less than 10, then the alphabets were converted to N. The following is the code. I find that my code does not loop over the tuple function in the last part of the code. It takes in only a single sequence and does not loop over the other tutorial = open('c:/test/z.txt','r') ## Input file looks like >qrst ABCDE-- 6 6 35 25 10 >qqqq

问题 I have two nested lists: ls1 = [["a","b"], ["c","d"]] ls2 = [["e","f"], ["g","h"]] and I'd like the following result [(a,e), (b,f), (c,g), (d,h)] I've tried zip(a,b), how do I zip nested lists into a list with tupled pairs? 回答1: You can also use itertools.chain.from_iterable and zip : >>> ls1 = [["a","b"], ["c","d"]] >>> ls2 = [["e","f"], ["g","h"]] >>> >>> zip(itertools.chain.from_iterable(ls1), itertools.chain.from_iterable(ls2)) [('a', 'e'), ('b', 'f'), ('c', 'g'), ('d', 'h')] 回答2: You

问题 I have a list like below L = [[1,2],[1,3],[1,4],[2,1],[2,5],[3,1],[3,2]] The output should be [[1,2],[1,3],[1,4],[2,5],[3,2]] Please note that the order for the pairs and the elements has to be preserved. In other words, I cannot sort the list because the elements order needs to be preserved for the pairs as well. For example, I need the last element [3,2] to be preserved. If i sort them and remove duplicates this will be changed to [2,3] which I do not want. Also when I say I need to remove

问题 I need to implement Comparison delegate for Tuple. And I have a column number by which I want to compare Tuples. For now I got to: int sortedColumn; Comparison<Tuple<T1, T2, T3>> tupleComparison = (x, y) => { // I want to access x.Item2 if sortedColumn = 2 // x.Item3 if sortedColumn = 2 etc }; How can I do this in c#? Can I do it without using switch ? 回答1: I'd probably go with if / else or switch , but if you want to avoid that (e.g. so you can use it with any Tuple ), you can use reflection

问题 This question is part B of my other question here: Inefficient MVC ViewModel Making Multiple Calls to the Database? I knew multiple calls to the db was a bad idea. But, I guess my real question is if I use my last chunk of code or speti43's example let's say like this in my model constructor to eliminate multiple db calls: Public Class OrdersSummary{ ... Public ???? GetOrders(){ var ordersInMemory = orders.ToList(); decimal? GrossProfitTotal = ordersInMemory.Sum(s => s.Profit); decimal?

问题 Storing items of the same type is trivial, but I need a container that can store items of different types. Here's an example showing what I'd like to do: Class C { }; C c1; C c2; C c3; std::tuple<C> tup1(c1); std::tuple<C, C> tup2(c1, c2); std::tuple<C, C, C> tup3(c1, c2, c3); container_type container(tup1, tup2, tup3); Is there any container that works in this way? If not, is there a way to create one? I'd like something that overloads operator[] for fast random access. 回答1: It won't work.

问题 I have made a small map that I call BMW . It contains the keys Usage and Diesel , as shown below. #include <iostream> #include <bits/stdc++.h> #include <map> #include <vector> using namespace std; int main() { // initialize container std::map<string, std::tuple<string, string>> BMW; // insert elements BMW.insert({"Usage", {"1", "2"}}); BMW.insert({"Disel", {"2", "3"}}); std::cout << "Usage => " << BMW.find('Usage')->second << '\n'; return 0; } What I want to do is to find the key Usage in the

问题 How to convert following list ['abc,cde,eg,ba', 'abc,cde,ba'] in to list of tuples? [('abc','cde','eg','ba'), ('abc','cde','ba')] What I have tried output = [] for item in my_list: a = "','".join((item.split(','))) output.append(a) 回答1: In your loop, you are splitting the string (which will give you a list), but then you are joining it back with a , , which is returning to you the same string: >>> 'a,b'.split(',') ['a', 'b'] >>> ','.join('a,b'.split(',')) 'a,b' You can convert a list to a