tuples

问题 How can I edit my code such that my output: the 8512 and 7759 i 6182 to 6027 a 4716 of 4619 he 2873 in 2846 you 2777 was 2457 becomes 1. the 8512 2. and 7759 3. i 6182 4. to 6027 5. a 4716 6. of 4619 7. he 2873 8. in 2846 9. you 2777 10. was 2457 I attempted to use the enumerate function for rank, (value,num) in enumerate(sorted_list): however this leaves me with the same output. Could I somehow append ranking into the list where value and num is defined? d = dictionary(word_list) def sort

问题 I'm trying to write a Haskell function that will take a String say "PLATYPUS" and will return the relative percentages of Characters in that word i.e. characterPercentages "PLATYPUS" would return: [(P,25),(A,13),(L,13),(S,13),(T,13),(U,13),(Y,13)]. I know I can use tuples, but after that I'm a bit stumped? 回答1: First, you need to understand what are you going to get. As I understand, you wish to have type String = [Char] --already in Prelude String -> [(Char,Int)] "PLATYPUS" -=> [('P',2),('A'

问题 Using the key-pair tuples from my_file.txt, create a dictionary. If a key exists multiple times with different values, use the first seen value (e.g., the first instance we encountered the key). my_file = [('a', '1') ('b', '2') ('c', '3') ('d', '4') ('e', '5')] def makehtml(fname): with open(fname) as f: # reads lines from a fname file for line in f: tups = line2tup(line,"--") # turns each line into a 2 elem tuple on it's own line. print tups How can I create a dictionary from my_file key

问题 I have a long list of nested tuples that I am iterating through and appending in a certain way such that an empty dictionary: dict = {} will be filled like this: dict = {a: {b:1,5,9,2,3}, b: {c:7,4,5,6,2,4}, c: {b:3,13,2,4,2}... } The iteration will check if a nested dictionary exists, and if so, then it will append the value, otherwise, create a nested dictionary. My poor attempt looks something like this: longlist = [(1,(a,b)),(2,(b,c)), (3,(c,b)) ... ] dict = {} for each in longlist: if

问题 Given a function that takes multiple arguments and returns multiple values as so: def tuple_unpack(value, another_value): ''' does some interesting stuff ... ''' return value, another_value Is there a way to apply such function to a pandas dataframe where for the 2 function arguments I can pass values from 2 columns, then unpack the output tuple on multiple colums as so: df[['value_col','another_value_col']] = df.apply(lambda df.col, df.col: tuple_unpack) 回答1: You can using concat , with

问题 I have a fixed size array of String s: [String; 2] . I want to turn it into a (String, String) . Can I do this without copying the values? The piece of code that I'm working on in particular is the following: let (basis, names_0, names_1) = if let Some(names) = self.arg_name { (ComparisonBasis::Name, names[0], names[1]) } else { (ComparisonBasis::File, self.arg_file[0], self.arg_file[1]) }; types: self.arg_name: Option<[String; 2]> self.arg_file: Vec<String> Right now I'm getting errors

问题 I have a class template template<class T> class A {...}; and I want to specialize it when T is a tuple. I think I can do this template<class Args...> class A<std::tuple<Args...>> {...}; However, my compiler doesn't support variadic template arguments, how to do it? 回答1: You can specialize it for tuples of every different arity: // explicit specialization for 0-element tuples template<> class A<std::tuple<>> {...}; // partial specialization for 1-element tuples template<class Arg> class A<std:

问题 I am fairly new to c++, I dont really have any background in it. I am tying to create a list of tuples, the first will be an int, the second will be a string. #include <string> #include <list> #include <boost/tuple/tuple.hpp> .... list< tuple<int,string> > time; And getting an error. I want to be able to create a list, add entries that I can sort by the int, and have the string that describes, what the int was. How would I create this list? 回答1: For a simple list use std::vector instead of

问题 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. Closed 7 years ago . supportData = {('ELF'): 0.75, ('CAT'): 0.75, ('BAT', 'CAT', 'ELF'): 0.5, ('ARK', 'BAT'): 0.25, ('ARK', 'ELF'): 0.25, ('CAT', 'ELF'): 0

问题 I'm trying to get this list of tuples: [(2,"a"), (1,"a"), (1,"b"), (1,"c"), (2,"dd")] into this string output a 1,2 b 1 c 1 dd 2 I assume I need to use the unzip and unlines functions. But I also saw some solutions using the show function which makes the integers strings. Any ideas? 回答1: Break the problem down into steps. What you really want to do first is aggregate all the tuples that have the same string in the second position, so you'll have a function like aggregate :: [(Int, String)] ->