tuples

问题 I have one class, class AClass . In this class I'm filling two dictionaries and also, I'm returning these two dictionaries so I've used Tuple<Dictionary<string, string>, Dictionary<string, string>> type of method declaration: class AClass { Dictionary<string, string> dictOne = new Dictionary<string, string>(); Dictionary<string, string> dictTwo = new Dictionary<string, string>(); public Tuple<Dictionary<string, string>, Dictionary<string, string>> MyMethodOne() { //Adding items dictOne and

问题 I have a dictionary named 'score' with keys that are tuples. Each tuple is of the form (x, y, tag). Some possible score initializations are: score[(0, 1, 'N')] = 1.0 score[(0, 1, 'V')] = 1.5 score[(0, 1, 'NP')] = 1.2 score[(1, 2, 'N')] = 0.2 score[(1, 2, 'PP')] = 0.1 score[(1, 2, 'V')] = 0.1 I'd like to be able to keep x and y constant (e.g. 0, 1) and then iterate over the given values for tag (e.g. N, V, NP). Any Python geniuses out there know of ways to do this? I'm looking for multiple

问题 How can I obtain the tuple type of the first elements in a given tuple type? If I only ask for one element, it should give me the inner type instead of a tuple type of one element. In code, how would I get the type I'm looking for? //TupleType is a tuple of n types 0,1,2,...,n-1 template<size_t i, typename TupleType> struct first_elements { using type = //the "sub-tuple" of types 0,1,2,...,i //exception: if i=0, just the bare type within //the tuple, not the tuple of one element }; Once

问题 I'm trying to write a program that will read in a text file and output a list of most common words (30 as the code is written now) along with their counts. so something like: word1 count1 word2 count2 word3 count3 ... ... ... ... wordn countn in order of count1 > count2 > count3 >... >countn. This is what I have so far but I cannot get the sorted function to perform what I want. The error I get now is: TypeError: list indices must be integers, not tuple I'm new to python. Any help would be

问题 I have a collection of internet-connected devices hanging around in various places. I have a dataframe that contains seven rows, one for each day in the past week. Each row contains the serial number of each device that didn't connect to my server that day. I am trying to compile a report that creates an 8th row, which contains the serial number of each device that failed to communicate for seven straight days. Here is a simplified mock-up of my dataframe: 2016-10-01, AAAA, BBBB, CCCC, EEEE

问题 I have a list of tuples which i want to group by one of its elements as a key. For example, if i had this list of tuples: [(A, "hello"), (A, "stack"), (A,"over"), (A, "flow"), (B, "how"), (B, "you"), (C, "doin")] I would like to get a result in the form: [(A, ["hello", "stack", "over", "flow"]), (B, ["how", "you"]), (C, ["doin"])] I am new to F# so I am all out of ideas on how to do this. I thank you in advance. cheers 回答1: I think you are using incorrect delimiter for list elements - instead

问题 I have the following dictionary and i want to count how many times keys appear, dictionary is very big. a = { (1,2):3, (1,3):5, (2,1):6 } and I want this result 1: 3 times 2: 2 times 3: 1 time 回答1: >>> from collections import Counter >>> a = { (1,2):3, (1,3):5, (2,1):6 } >>> >>> Counter(j for k in a for j in k) Counter({1: 3, 2: 2, 3: 1}) 回答2: Use itertools.chain and a collections.Counter: collections.Counter(itertools.chain(*a.keys())) Alternatively: collections.Counter(itertools.chain.from

问题 this is my part of code to parse a NMEA data ( source here Plot chart using values from richTextBox C#) . This function get back latitude from richTextBox, and convert it to decimal notation. I need it, to plot charateristic from 4 another GPS module (to compare accuracy all four GPS). This is my problem. I want to use a "numericUpDown" to change Math.Round (below I have value - 11). I cant get inside Tuple because I have error (I tried to do something, but it didnt work). Can anybody know,

问题 When comparing tuples of objects apparently the __eq__ method of the object is called and then the compare method: import timeit setup = """ import random import string import operator random.seed('slartibartfast') d={} class A(object): eq_calls = 0 cmp_calls = 0 def __init__(self): self.s = ''.join(random.choice(string.ascii_uppercase) for _ in range(16)) def __hash__(self): return hash(self.s) def __eq__(self, other): self.__class__.eq_calls += 1 return self.s == other.s def __ne__(self,

问题 Say I created a tuple like this using a byte array: import struct a = struct.unpack('f', 'helo') How can I now convert a into a float? Any ideas? 回答1: struct.unpack always returns a tuple, because you can unpack multiple values, not just one. A tuple is a sequence, just like a list, or any other kind of sequence. So, you can index it: >>> a = struct.unpack('f', 'helo') >>> b = a[0] >>> b 7.316105495173273e+28 … or use assignment unpacking: >>> b, = a >>> b 7.316105495173273e+28 … or loop over