tuples

问题 I would like to constrain a (tuple) array in JSON-schema, and get decent error messages but so far I was unsuccessful. The array consists of 2 items, the first is a string, and the second is an object. The properties that are allowed/required in the object depends on the string. 2 valid examples would be: { "color": [ "white", { "a white property": 42 }] } and { "color": [ "black", { "this is a black property": "tAttUQoLtUaE" }] } for reference, the type in typescript would be defined as:

问题 val test1 = [(1,5,3),(3,5,2),(3,4,5)] fun number_in_month dates_and_month = case dates_and_month of (x,y,z)::xs' => y :: number_in_month xs' This code produces the following error when I run in the REPL with test1: uncaught exception Match [nonexhaustive match failure] raised at: hw1pm.sml:28.49 Any clue why? 回答1: It did not know what do when the list was empty. Working code: fun number_in_month dates_and_month = case dates_and_month of [] => [] | (x,y,z)::xs' => y :: number_in_month xs' 回答2:

问题 No offence, if the questions is too basic. Let me know if you need more information. I am looking for an idea to convert square-form tuple of tuples to pandas.DataFrame in a clean/efficient/pythonic way, i.e. from s =((1,0,0,0,),(2,3,0,0,),(4,5,6,0,),(7,8,9,10,)) to pandas.DataFrame like 1 2 3 4 1 1 0 0 0 2 2 3 0 0 3 4 5 6 0 4 7 8 9 10 Naturally, this list can grow with more zeros appended in the upper-triangular (if we think of s as a tuple of rows). DataFrame(t) seems to fail. 回答1: import

问题 So I have a tuple of tuples a = ((1, 2), (7, 2), (5, 2), (3, 4), (8, 4)) I would like to remove all the tuples from 'a' which have the a common second element, except for one (any one of them). For the example above I would like the new output a = ((1,2),(3,4)) In other words I would like to eliminate tuples which are considered duplicate elements in the second position of the tuple. I would like to know the most efficient way to achieve this, and also like to know if I can do the same with

问题 Sometimes there are needs to create tuples from small collections(for example scalding framework). def toTuple(list:List[Any]):scala.Product = ... 回答1: If you don't know the arity up front and want to do a terrible terrible hack, you can do this: def toTuple[A <: Object](as:List[A]):Product = { val tupleClass = Class.forName("scala.Tuple" + as.size) tupleClass.getConstructors.apply(0).newInstance(as:_*).asInstanceOf[Product] } toTuple: [A <: java.lang.Object](as: List[A])Product scala>

问题 I have a tuble like this as model. @model Tuple<Urun,List<UrunKatagori>> inside the view I need to pass those data to controler. here is the my button. Html.X().Button().Text("Guncelle").Icon(Icon.PageSave) .DirectEvents(de => { de.Click.Url = "Urunler/Guncelle"; de.Click.ExtraParams.Add(new Parameter { Name = "Urun", Value ="Model.Item1", Mode = ParameterMode.Raw });//Iguess here is wrong }) and my controller [HttpPost] public ActionResult Guncelle (Urun Urun){ Urun_BLL urun_bll = new Urun

问题 This question already has answers here : Find intersection of two nested lists? (19 answers) Is there a way to get the difference and intersection of tuples or lists in Python? [duplicate] (1 answer) Closed 2 years ago . I have 2 tuples A & B. How can I extract the common elements of A & B to form a new tuple? For example: A -> (1,'a',(2,'b'),3,'c',4) B -> (1,(2,'b'),4,8) new_tuple -> (1,(2,'b'),4) Thanks. 回答1: With set intersection (to return a new set with elements common to the set and all

问题 I'm attempting to transform a Tuple union in TypeScript to an object, without losing any types. Here is an example of how it would work: type Tuples = ["foo", string] | ["bar", boolean] | ["baz", null]; /* ideally the type would be: { foo: string; bar: boolean; baz: null; } */ type AsObject = DoSomething<Tuples>; A simple solution to the above would be: type TupleToObject<T extends [string, any]> = { [key in T[0]]: T[1] }; /* type is: { foo: string | boolean | null; bar: string | boolean |

问题 I'm attempting to transform a Tuple union in TypeScript to an object, without losing any types. Here is an example of how it would work: type Tuples = ["foo", string] | ["bar", boolean] | ["baz", null]; /* ideally the type would be: { foo: string; bar: boolean; baz: null; } */ type AsObject = DoSomething<Tuples>; A simple solution to the above would be: type TupleToObject<T extends [string, any]> = { [key in T[0]]: T[1] }; /* type is: { foo: string | boolean | null; bar: string | boolean |

问题 Can multiple members be initialized in the member initializer list from a tuple obtained by a function? With returning multiple values via tuples becoming more popular I hope there is a solution for this. I see no reason other than a language limitation why this would not be possible. This is a mcve for what I have: auto new_foo(std::size_t size) -> std::tuple<std::unique_ptr<char[]>, int*> { auto buffer = std::make_unique<char[]>(size * sizeof(int) + 8); auto begin = static_cast<int*>(static