tuples

I have a list of some tuples. Each tuple has three elements. I need to sort the list. To break tie between two tuples, first element of tuple is looked then if still tied then the second element. List is like below. L = [(1, 14, 0), (14, 1, 1), (1, 14, 2), (14, 2, 3), (2, 4, 4), (4, 11, 5), (11, -1000, 6)] In C the sort function takes a compare function and that does everything simply. But I couldn't figure it out after trying for sometimes in python . Can anybody help me? Martijn Pieters Just sort the list; the default sort does just what you want. When comparing two tuples, they are ordered

I get back good results from the following, but how to I extract that data from the tuple? In other words, how do I clean up the data? Here is the data from the database, I ran out. >>> policy_id = ((2309L,), (118L,), (94L,)) >>> for i in policy_id: print i (2309L,) (118L,) (94L,) But I want the result as: 2309 118 94 policy_id = ((2309L,), (118L,), (94L,)) for i in policy_id: print i[0] >>> from itertools import chain >>> policy_id = ((2309L,), (118L,), (94L,)) >>> for i in chain.from_iterable(policy_id): print i 2309 118 94 print '\n'.join(str(x[0]) for x in policy_id) A notion that I like,

I've been working with some relatively complex arrays such as: array = [ "1", 2, ["4", "5", ("a", "b")], ("c", "d")] and I was looking for a way to find an item and retrieve is "index" (Is it OK to refer to the location of item such as "a" - that is inside a Tuple as index on the same level as array?) Now my first thought was to use something like a simple helper function such as: def myindex(nestedlist, item): for i in nestedlist: if item in i: index = [] index.append(i) index.append(i.index(item)) return index But I'm sure you can guess that such a function won't do much good, especially

Sorry if this is trivial - I am so new to swift, actually I have only looked at the language guide+reference for a few minutes. As far as I understand a parenthesized expression like (2,3) is used to construct a tuple, and (2) is a single-element tuple of type (Int) . But then what happens with common use of parentheses like (2+4) in expression (2+4)*5 ? Is this still a tuple of type (Int) multiplied by an Int ? From Types in the Swift book: If there is only one element inside the parentheses, the type is simply the type of that element. For example, the type of (Int) is Int , not (Int) . So

If I have list of tuples like this: my_list = [('books', '$5'), ('books', '$10'), ('ink', '$20'), ('paper', '$15'), ('paper', '$20'), ('paper', '$15')] how can I turn the list to this: [('books', '$15'), ('ink', '$20'), ('paper', '$50')] i.e. to add the expense of same item while both the items are string in the tuples. I have problem with the price items being string. Any hint would be greatly appreciated. Thanks a lot! I am getting the first list in this way: my_list=[] for line in data: item, price = line.strip('\n').split(',') cost = ["{:s}".format(item.strip()), "${:.2f}".format(float

i have a tuple like this [ (379146591, 'it', 55, 1, 1, 'NON ENTRARE', 'NonEntrate', 55, 1), (4746004, 'it', 28, 2, 2, 'NON ENTRARE', 'NonEntrate', 26, 2), (4746004, 'it', 28, 2, 2, 'TheBestTroll Group', 'TheBestTrollGroup', 2, 3) ] i would like to get instead this: [ (379146591, (('it', 55, 1, 1, 'NON ENTRARE', 'NonEntrate', 55, 1)), (4746004, (('it', 28, 2, 2, 'NON ENTRARE', 'NonEntrate', 26, 2), ('it', 28, 2, 2, 'TheBestTroll Group', 'TheBestTrollGroup', 2, 3))) ] so the for any element, anything that is not the first element is inside a sub-tuple of it, and if the following element has the