tuples

I just read the question Why is there no tuple comprehension in Python? In the comments of the accepted answer , it is stated that there are no true "tuple comprehensions". Instead, our current option is to use a generator expression and pass the resulting generator object to the tuple constructor: tuple(thing for thing in things) Alternatively, we can create a list using a list comprehension and then pass the list to the tuple constructor: tuple([thing for thing in things]) Lastly and to the contrary of the accepted answer, a more recent answer stated that tuple comprehensions are indeed a

I have a list of tuples that reads as such: >>>myList [(), (), ('',), ('c', 'e'), ('ca', 'ea'), ('d',), ('do',), ('dog', 'ear', 'eat', 'cat', 'car'), ('dogs', 'cars', 'done', 'eats', 'cats', 'ears'), ('don',)] And I would like it to read as such: >>>myList [('',), ('c', 'e'), ('ca', 'ea'), ('d',), ('do',), ('dog', 'ear', 'eat', 'cat', 'car'), ('dogs', 'cars', 'done', 'eats', 'cats', 'ears'), ('don',)] i.e. I would like to remove the empty tuples () from the list. While doing this I want to preserve the tuple ('',) . I cannot seem to find a way to remove these empty tuples from the list. I have

Have a look at these scala snippets: if we have something like this: List(List(1, 2), List(3, 4), List(5)) map (x => (x.size)) we can shorten it to: List(List(1, 2), List(3, 4), List(5)) map ((_.size)) but, if we have something like this: List(List(1, 2), List(3, 4), List(5)) map (x => (x.size, x.size)) why can't we shorten it to: List(List(1, 2), List(3, 4), List(5)) map ((_.size, _.size)) ? An amount of placeholders should be equals amount of function parameters. In your case map has 1 parameter that's why you can't use two placeholders. Because List(List(1, 2), List(3, 4), List(5)) map ((_

I've got a query result of List[(Int,String,Double)] that I need to convert to a Map[String,String] (for display in an html select list) My hacked solution is: val prices = (dao.getPricing flatMap { case(id, label, fee) => Map(id.toString -> (label+" $"+fee)) }).toMap there must be a better way to achieve the same... A little more concise: val prices = dao.getPricing.map { case (id, label, fee) => ( id.toString, label+" $"+fee)} toMap shorter alternative: val prices = dao.getPricing.map { p => ( p._1.toString, p._2+" $"+p._3)} toMap How about this? val prices: Map[String, String] = dao

Can anyone help the following List Tuple more than 8 elements is not working: List<Tuple<int, string, double, string, int, string, double, Tuple<int, string>>> tpl = new List<Tuple<int, string, double, string, int, string, double, Tuple<int, string>>>(); tpl.Add(Tuple.Create(1, "ABC", 100.123, "XYZ", 1, "ABC", 100.123, new Tuple<int, string>(100, "My Rest Item"))); foreach(var k in tpl) listBox1.Items.Add(k.Item1.ToString() + " ---> " + k.Item2.ToString() + " ---> " + k.Item3.ToString() + " ---> " + k.Item4.ToString() + " ---> " + k.Item5.ToString() + " ---> " + k.Item6.ToString() + " ---> " +

I am currently trying to sort the following list: list_ = [(1, '0101'), (1, '1010'), (1, '101'), (2, '01'), (2, '010'), (2, '10')] These are the steps I want to take in order to sort it: Sort the list by the value of the first element of the tuples Next, sort the list by the length of the second element of the tuples (not the value, the length!) AFTER step 1 finishes. Next, sort the list by the value of the second element of the tuples AFTER step 1 and step 2 finishes. My attempt: sorted_by_length = sorted(list_, key=len x:x[1]) However, I received a syntax error concerning the x after key=