traversal

private void jTextField1KeyPressed(java.awt.event.KeyEvent evt) { //cant capture my TAB? System.out.print(evt.getKeyChar()); } What is the simplest way in an java gui to capture the tab key without doing using the focus listening technique? VK_TAB is the tab constant. However: No Tab key-pressed or key-released events are received by the key event listener. This is because the focus subsystem consumes focus traversal keys, such as Tab and Shift Tab. See: http://docs.oracle.com/javase/tutorial/uiswing/events/keylistener.html To solve this, apply the following to the component that is firing the

Is it possible to perform complex queries over a JSON object? I am open to JavaScript or jQuery solutions, the easier the better. I'm envisioning some kind of functional programming language similar to LINQ or SQL. I Prefer no other third party libraries or add-ons. UPDATE From the looks of early answers, an add-on is going to be necessary. In that case, I prefer an add-on that requires no installation process. Something that deploys with the software publish (like jQuery) is fine (e.g. sets of *.js files). Ryan Ternier Check out: Is there a query language for JSON? From that thread: JaQL (

Okay, Now I have an unordered list here: <ul id="mycustomid"> <li><a href="url of Item A" title="sometitle">Item A</a> <ul class="children"> <li><a href="url of Child1 of A" title="sometitle">Child1 of A</a> <ul class="children"> <li><a href="url of Grandchild of A" title="sometitle">Grandchild of A</a> <ul class="children"> <li><a href="url of Grand Grand child of A" title="sometitle">Grand Grand child of A</a></li> </ul> </li> </ul> </li> </ul> </li> <li><a href="url of Item B" title="sometitle">Item B</a></li> <li><a href="url of Item C" title="sometitle">Item C</a></li> </ul> Basically, I

How can I construct a tree given its inorder and preorder traversal? I am just looking for an efficient algorithm. A blatant copy and paste from Sun's (Oracle now, I guess...) forum : Question: Can anybody help me on how to construct Binary tree from inorder and postorder traversals,i just want to know the algorithm so that i can apply it. Answer: Let p_1 , p_2 ... p_n be the postorder traversal and let i_1 , i_2 ... i_n be the inorder traversal. From the postorder traversal we know that the root of the tree is p_n . Find this element in the inorder traversal, say i_1 , i_2 ... i_k-1 p_n i_k+1

TL;DR: How do I get an action like find(), but block traversal (not full stop, just skip) for a certain selector? ANSWERS: $(Any).find(Selector).not( $(Any).find(Mask).find(Selector) ) There were many truly great answers, I wish I could some how distribute the bounty points more, maybe I should make some 50 pt bounties in response to some of these ;p I choose Karl-André Gagnon's because this answer managed to make findExclude unrequired in one, slightly long, line. While this uses three find calls and a heavy not filter, in most situations jQuery can use very fast implementation that skips

I want to find the first span element after class counter, in code something like this: <div class="counter"></div> <p></p> <span></span> It seems like the next() function only finds the immediate next element, so something like this: $(".counter").next("span") Won't work. The way I have been using is a bit lengthy and I was wondering if there was a shorter way, it is this: $(".counter").nextAll("span").eq(0) I think the closest() method in jQuery 3 will do the trick, but I am using 1.2.6 -- is there a better way to do this (am I just using next() wrong?) Pim Jager I think your method is the

I'm looking for a way to gather all of the text in a jQuery wrapped set, but I need to create spaces between sibling nodes that have no text nodes between them. For example, consider this HTML: <div> <ul> <li>List item #1.</li><li>List item #2.</li><li>List item #3.</li> </ul> </div> If I simply use jQuery's text() method to gather the text content of the <div> , like such: var $div = $('div'), text = $div.text().trim(); alert(text); that produces the following text: List item #1.List item #2.List item #3. because there is no whitespace between each <li> element. What I'm actually looking for