time

php convert a date to a timestamp

生来就可爱ヽ(ⅴ<●) 提交于 2020-01-15 11:56:08
问题 I'm trying to convert 2 dates to timestamps. One is generated by php (today's date) and the other is input by the user $today = date("d-m-y"); // 01-12-13 $start_date = "28-11-13"; $todaytimestamp = strtotime($today); $starttimestamp = strtotime($start_date); echo "$today > $start_date <br>$todaytimestamp > $starttimestamp"; Problem is that the result are incorrect Result: 01-12-13 > 28-11-13 1008201600 > 1857686400 what's wrong ? 回答1: Always use four-digit years, as using two-digit years

Difference between two time resulting an error

こ雲淡風輕ζ 提交于 2020-01-15 11:18:26
问题 I have this situation, i want to calculate the late of an employee and to get the late, i need to Subtract time to get the minute/hour late of an employee. Suppose to be.. i have this code: $time = strtotime($time_in); $late_time = date("H:i", strtotime('+15 minutes', $time)); if(date("H:i:s",strtotime($time_duty[0]->time)) > $late_time ) { $time_difference = (date("H:i:s",strtotime($time_duty[0]->time)) - $late_time)/60; print_r($time_difference); } then i've encountered error Message: A non

Difference between two time resulting an error

自古美人都是妖i 提交于 2020-01-15 11:18:08
问题 I have this situation, i want to calculate the late of an employee and to get the late, i need to Subtract time to get the minute/hour late of an employee. Suppose to be.. i have this code: $time = strtotime($time_in); $late_time = date("H:i", strtotime('+15 minutes', $time)); if(date("H:i:s",strtotime($time_duty[0]->time)) > $late_time ) { $time_difference = (date("H:i:s",strtotime($time_duty[0]->time)) - $late_time)/60; print_r($time_difference); } then i've encountered error Message: A non

How can i interpret “FoxPro” dbf file date time field (eight-byte) in my c++ program?

大憨熊 提交于 2020-01-15 11:14:12
问题 I am writing a c++ program to read DBF file of foxpro database .I stumbled upon this date time field of eight bytes.How can i interpret it ? Any help would be highly appreciated ? 回答1: The value is a double The integer part is the day since 1899/12/30 internal const double JulianDay_1899_12_30 = 2415019.0; double d = theValue; in c# return DateTime.FromOADate(d - JulianDay_1899_12_30); see http://msdn.microsoft.com/en-us/library/system.datetime.fromoadate.aspx 来源: https://stackoverflow.com

How can i interpret “FoxPro” dbf file date time field (eight-byte) in my c++ program?

时光毁灭记忆、已成空白 提交于 2020-01-15 11:12:35
问题 I am writing a c++ program to read DBF file of foxpro database .I stumbled upon this date time field of eight bytes.How can i interpret it ? Any help would be highly appreciated ? 回答1: The value is a double The integer part is the day since 1899/12/30 internal const double JulianDay_1899_12_30 = 2415019.0; double d = theValue; in c# return DateTime.FromOADate(d - JulianDay_1899_12_30); see http://msdn.microsoft.com/en-us/library/system.datetime.fromoadate.aspx 来源: https://stackoverflow.com

How can i interpret “FoxPro” dbf file date time field (eight-byte) in my c++ program?

▼魔方 西西 提交于 2020-01-15 11:12:02
问题 I am writing a c++ program to read DBF file of foxpro database .I stumbled upon this date time field of eight bytes.How can i interpret it ? Any help would be highly appreciated ? 回答1: The value is a double The integer part is the day since 1899/12/30 internal const double JulianDay_1899_12_30 = 2415019.0; double d = theValue; in c# return DateTime.FromOADate(d - JulianDay_1899_12_30); see http://msdn.microsoft.com/en-us/library/system.datetime.fromoadate.aspx 来源: https://stackoverflow.com

How to add extra time into the time column with data using python

白昼怎懂夜的黑 提交于 2020-01-15 10:27:29
问题 Here I have a dataset with date, time and one input column. So here my time column is not good. So I want to give time range into that time column. So here first I did I just convert start time into 0 and convert whole time column into minutes. Then next what I want to give time range like 0,60,120.... Mean what I expected output is: first time convert date time time 10/3/2018 6:15:00 0 10/3/2018 6:45:00 30 10/3/2018 7:45:00 90 10/3/2018 9:00:00 165.0 10/3/2018 9:25:00 190.0 10/3/2018 9:30:00

How to add extra time into the time column with data using python

て烟熏妆下的殇ゞ 提交于 2020-01-15 10:27:19
问题 Here I have a dataset with date, time and one input column. So here my time column is not good. So I want to give time range into that time column. So here first I did I just convert start time into 0 and convert whole time column into minutes. Then next what I want to give time range like 0,60,120.... Mean what I expected output is: first time convert date time time 10/3/2018 6:15:00 0 10/3/2018 6:45:00 30 10/3/2018 7:45:00 90 10/3/2018 9:00:00 165.0 10/3/2018 9:25:00 190.0 10/3/2018 9:30:00

MySQL / PHP: catch all entries between 2 times and check against 2 other times

人盡茶涼 提交于 2020-01-15 09:54:07
问题 I have a database where people can book rooms within two certain times, but there may be other people searching for an available room within the same times - or partly in the same time. Database looks like this: order | room | user | date (date-format) | from (time) | to (time) 1 123 foo 2013-04-04 12:00:00 17:00:00 The problem comes when another user searches if the room is available from f.ex 13:00 to 18:00, since I only manage to search if the room is available in the exact same time. The

How to convert array into 64bit Double Mac Absolute Time using Ruby?

╄→гoц情女王★ 提交于 2020-01-15 09:11:28
问题 Is it possible to convert Array having binary or hex values stored as each element into 64bit Double Mac Absolute Time? When I inspect array using p var_bytes console shows following output. \000\000\000\000\000\000\000\000\000\000\000\234\225x\266A\000\000\000\345\005\230\264 Is it possible to convert above array elements in 64bit Double Mac Absolute Time as a string? My code is following just a simple do..end puts "\nClose off the page header#{y.unpack("n")}\n" z.scan(/(.{8})(.{8})(.{4})(.