time

问题 In python, by importing datetime module and using various functions of class datetime.datetime we could get basic dates with formatting and even date arithmetic for deployment. For example, datetime.datetime.now() will return today's date. But, today when I run this program there was no internet connection in my computer but still it outputs today's date. So, how datetime.datetime.now() could return proper date? Is the algorithm automatically increment after 24 hours time ? 回答1: tl;dr

问题 I have a PHP script that has function allows for the seller to choose a delivery time for his listing I finally found it in the backend it was adding days to the delivery time title EX(if I created a row in the SQL table named 20 Min it takes (20) and add to it days so when the countdown start it count from 20 days) so I changed this in PHP file in the backend from this: $order_time = date("M d, Y H:i:s", strtotime($date_time . " + $add_days days")); to this: $order_time = date("M d, Y H:i:s"

问题 I have a PHP script that has function allows for the seller to choose a delivery time for his listing I finally found it in the backend it was adding days to the delivery time title EX(if I created a row in the SQL table named 20 Min it takes (20) and add to it days so when the countdown start it count from 20 days) so I changed this in PHP file in the backend from this: $order_time = date("M d, Y H:i:s", strtotime($date_time . " + $add_days days")); to this: $order_time = date("M d, Y H:i:s"

问题 I'm trying to add five minutes to the current time using milliseconds and am baffled why adding and subtracting give such different results: const now = new Date(); const gimmeFive = now + 300000; const takeFive = now - 300000; Respectively give: "Sun May 31 2020 23:06:48 GMT+0100 (British Summer Time)300000" 1590962508207 Why does subtraction work, but not addition? How can I add time? Added clarification per stack overflow prompt: while the Q here overlapped with Add 10 seconds to a Date,

问题 I have an instant formatted like this: DateTimeFormatter formatter = DateTimeFormatter.ofLocalizedDateTime(FormatStyle.SHORT ) .withLocale( Locale.UK ) .withZone( ZoneId.of("UTC")); String instant = formatter.format(Instant.now()).toString(); and i want to calculate the days, hours and minutes (if possible) between the instant and Instant.now(), something like: // for days String daysBetween = Instant.now() - instant; can i do that ? 回答1: To calculate days , hours and/or minutes between two

问题 I'm trying to implement a condition where if the count of incorrect values is greater than 2 (2019-05-17 & 2019-05-20 in the example below) then the complete date (all the time blocks) is removed Input t_value C/IC 2019-05-17 00:00:00 0 incorrect 2019-05-17 01:00:00 0 incorrect 2019-05-17 02:00:00 0 incorrect 2019-05-17 03:00:00 4 correct 2019-05-17 04:00:00 5 correct 2019-05-18 01:00:00 0 incorrect 2019-05-18 02:00:00 6 correct 2019-05-18 03:00:00 7 correct 2019-05-19 04:00:00 0 incorrect

问题 I have this below functionin my webapp to check if from OPEN to CLOSE time has elapse using a country timezone and it's working fine. Am trying to optimize my website, so my question is how can i make a function like this in javascript without the use of moment timezone? The moment timezone file is large and this is the only usage of it on my website. function isOpen(openTime, closeTime, timezone) { // handle special case if (openTime === "24HR") { return "open"; } // get the current date and

问题 In time column, there are values like: Time ======== 59:47 59:52 59:53 59:55 1:00:01 1:00:03 1:00:12 Now, I need to reshape the values like hh:mm:ss I have tried something like this: time_list = df7['Time'].tolist() for i in time_list: print(datetime.strptime(i,'%H:%M:%S')) ValueError: time data ' 36:21' does not match format '%H:%M:%S' 回答1: If you can normalise your values to always be of the form mm:ss or hh:mm:ss , with no additional components to them, then it's as simple as doing

问题 In time column, there are values like: Time ======== 59:47 59:52 59:53 59:55 1:00:01 1:00:03 1:00:12 Now, I need to reshape the values like hh:mm:ss I have tried something like this: time_list = df7['Time'].tolist() for i in time_list: print(datetime.strptime(i,'%H:%M:%S')) ValueError: time data ' 36:21' does not match format '%H:%M:%S' 回答1: If you can normalise your values to always be of the form mm:ss or hh:mm:ss , with no additional components to them, then it's as simple as doing

问题 I am attempting to get a matplotlib plotting function to be able to produce a graph with the x-axis set as a time axis. However, when I attempt to plot some values against UNIX times, I encounter the error ValueError: year is out of range . What is going wrong and how can it be addressed? import os import time import matplotlib.dates import matplotlib.pyplot import shijian def main(): data = [ [1484611200.0, 844.4333], [1484524800.0, 783.3373], [1484438400.0, 774.194 ], [1484352000.0, 769