ternary

Users, I'd like to have some tips for a ternaryplot ("vcd"). I have this dataframe: a <- c(0.1, 0.5, 0.5, 0.6, 0.2, 0, 0, 0.004166667, 0.45) b <- c(0.75,0.5,0,0.1,0.2,0.951612903,0.918103448,0.7875,0.45) c <- c(0.15,0,0.5,0.3,0.6,0.048387097,0.081896552,0.208333333,0.1) d <- c(500,2324.90,2551.44,1244.50, 551.22,-644.20,-377.17,-100, 2493.04) df <- data.frame(a, b, c, d) and I'm building a ternary plot: ternaryplot(df[,1:3], df$d) How can I map the continuous variable d , obtaining a result similar to this one? This is probably not the most elegant way to do this but it works (from scratch and

I wrote the absolute function using ternary operator as follows int abs(int a) { a >=0 ? return a : return -a; } I get the following error messages ../src/templates.cpp: In function ‘int abs(int)’: ../src/templates.cpp:4: error: expected primary-expression before ‘return’ ../src/templates.cpp:4: error: expected ‘:’ before ‘return’ ../src/templates.cpp:4: error: expected primary-expression before ‘return’ ../src/templates.cpp:4: error: expected ‘;’ before ‘return’ ../src/templates.cpp:4: error: expected primary-expression before ‘:’ token ../src/templates.cpp:4: error: expected ‘;’ before ‘:’

Is it possible to do this on one line in Python? if <condition>: myList.append('myString') I have tried the ternary operator: myList.append('myString' if <condition>) but my IDE ( MyEclipse ) didn't like it, without an else . Yes, you can do this: <condition> and myList.append('myString') If <condition> is false, then short-circuiting will kick in and the right-hand side won't be evaluated. If <condition> is true, then the right-hand side will be evaluated and the element will be appended. I'll just point out that doing the above is quite non-pythonic, and it would probably be best to write

Just spent a frustrating couple of hours debugging this code: LinkedHashMap<String, Integer> rsrqs = new LinkedHashMap<String, Integer>(); Integer boxedPci = 52; Integer boxedRsrq = boxedPci != null ? rsrqs.get(boxedPci.toString()) : -1; The above produces a NullPointerException. The below code doesn't: LinkedHashMap<String, Integer> rsrqs = new LinkedHashMap<String, Integer>(); Integer boxedPci = 52; Integer boxedRsrq = boxedPci != null ? rsrqs.get(boxedPci.toString()) : Integer.valueOf(-1); The only difference is wrapping the -1 with Integer.valueOf(). I'm sure I'm going to smack my forehead

I tripped across a really strange NullPointerException the other day caused by an unexpected type-cast in the ternary operator. Given this (useless exemplary) function: Integer getNumber() { return null; } I was expecting the following two code segments to be exactly identical after compilation: Integer number; if (condition) { number = getNumber(); } else { number = 0; } vs. Integer number = (condition) ? getNumber() : 0; . Turns out, if condition is true , the if -statement works fine, while the ternary opration in the second code segment throws a NullPointerException . It seems as though

Is there a way to do a java ternary operation without doing an assignment or way to fake the assingment? I like how succinct ternary code looks when doing a bunch of if/then/elses. I'm hoping to be able to call one of two void functions based on a boolean algebra statement. Something like: (bool1 && bool2) ? voidFunc1() : voidFunc2(); My functions are of return type void , so if there is a way to fake this in an assignment to make it work, then I"m okay with that... I would like to see how to do it though :) Nope you cannot do that. The spec says so . The conditional operator has three operand

I was writing a console application that would try to "guess" a number by trial and error, it worked fine and all but it left me wondering about a certain part that I wrote absentmindedly, The code is: #include <stdio.h> #include <stdlib.h> int main() { int x,i,a,cc; for(;;){ scanf("%d",&x); a=50; i=100/a; for(cc=0;;cc++) { if(x<a) { printf("%d was too big\n",a); a=a-((100/(i<<=1))?:1); } else if (x>a) { printf("%d was too small\n",a); a=a+((100/(i<<=1))?:1); } else { printf("%d was the right number\n-----------------%d---------------------\n",a,cc); break; } } } return 0; } More specifically