ternary-operator

While experimenting with ternary and null coalesce operators in C# I discovered that it is possible to use assignments on the right-hand side of expressions, for example this is a valid C# code: int? a = null; int? b = null; int? c = a ?? (b = 12); int? d = a == 12 ? a : (b = 15); Strangely enough, not only the assignment on the right-hand side of the expression is evaluated to its own right-hand side (meaning that the third line here is evaluated to 12 and not to something like b = 12 => void ), but this assignment also effectively works, so that two variables are assigned in one statement.

Why the ternary operator cannot be used to initialize a structure type, while it can be used to initialize a base type like int ? Example code : #include <stdio.h> #define ODD 1 int main(int argc, const char *argv[]) { static struct pair_str { int first; int second; } pair = ( ODD ) ? {1,3} : {2,4}; // ERROR printf("pair %d %d\n", pair.first, pair.second); int number = (ODD) ? 1 :2; // FINE return 0; } Compiler errors : /home/giuseppe/struct.c: In function ‘main’: /home/giuseppe/struct.c:12:23: error: expected expression before ‘{’ token /home/giuseppe/struct.c:12:29: error: expected

In C# I could easily write the following: string stringValue = string.IsNullOrEmpty( otherString ) ? defaultString : otherString; Is there a quick way of doing the same thing in Python or am I stuck with an 'if' statement? In Python 2.5, there is A if C else B which behaves a lot like ?: in C. However, it's frowned upon for two reasons: readability, and the fact that there's usually a simpler way to approach the problem. For instance, in your case: stringValue = otherString or defaultString @Dan if otherString: stringValue = otherString else: stringValue = defaultString This type of code is

This question already has an answer here: Swift ternary operator compilation error 2 answers I have an array of Doubles, and a button which when pressed empties the array. I want the button to be enabled only when the count of the array is greater than zero. The code is the following: var numbers: [Double] = [] //At some point I add some numbers here numbers.count > 0 ? deleteAllNumbersButton.isEnabled = true : deleteAllNumbersButton.isEnabled = false The compiler complains: Result values in '? :' expression have mismatching types '()' and 'Bool' When put in an if statement it works just fine

Consider this code snippet: public static void main(String[] args) { int z1 = 0; final int z2 = 0; System.out.println(false ? z1 : 'X'); System.out.println(false ? z2 : 'X'); } When running this code, I would expect to see two X in your console. However, the real output is: 88 X If we take a look at the Java specifications regarding the ternary operator , we found that If one of the operands is of type T where T is byte, short, or char, and the other operand is a constant expression of type int whose value is representable in type T, then the type of the conditional expression is T. So the