teradata

I am just starting on Teradata and I have come across an Ordered Analytical Function called "Rows unbounded preceding" in Teradata. I tried several sites to learn about the function but all of them uses a complicated example explaining the same. Could you please provide me with a naive example so that I can get the basics clear. It's the "frame" or "range" clause of window functions, which are part of the SQL standard and implemented in many databases, including Teradata. A simple example would be to calculate the average amount in a frame of three days. I'm using PostgreSQL syntax for the

Can we delete duplicate records from a multiset table in teradata without using intermediate table. Suppose we have 2 rows with values 1, 2, 3 and 1, 2, 3 in my multiset table then after delete i should have only one row i.e. 1, 2, 3. You can't unless the ROWID usage has been enabled on your system (and probablity is quite low). You can easily test it by trying to explain a SELECT ROWID FROM table; Otherwise there are two possible ways. Low number of duplicates: create a new table as result of SELECT all columns FROM table GROUP BY all columns HAVING COUNT(*) > 1; DELETE FROM tab WHERE EXISTS

Is there any way to submit dynamically generated SQL to Teradata? I've written a query that will create the code to denormalize a table. Right now, I am pulling the code down to my client (SAS) and resubmitting it in a second step. I am not familiar with either Teradata macros or procedures; would something like that work? To illustrate, I have a table defined like this: create multiset table MYTABLE ( RECID integer generated always as identity ( start with 1 increment by 1 minvalue -2147483647 maxvalue 2147483647 no cycle ) , SNAP_DATE date format 'YYYY/MM/DD' , EMAIL_DATE date format 'YYYY

I am trying to compare two addresses from the same ID to see whether they match. For example: Id Adress Code Address 1 1 123 Main 1 2 123 Main 2 1 456 Wall 2 2 456 Wall 3 1 789 Right 3 2 100 Left I'm just trying to figure out whether the address for each ID matches. So in this case I want to return just ID 3 as having a different address for Address Code 1 and 2. Join the table with itself and give it two different aliases ( A and B in the following example). This allows to compare different rows of the same table. SELECT DISTINCT A.Id FROM Address A INNER JOIN Address B ON A.Id = B.Id AND A.

I'm attempting to use python with sqlalchemy to download some data, create a temporary staging table on a Teradata Server, then MERGEing that table into another table which I've created to permanently store this data. I'm using sql = slqalchemy.text(merge) and td_engine.execute(sql) where merge is a string similar to the below: MERGE INTO perm_table as p USING temp_table as t ON p.Id = t.Id WHEN MATCHED THEN UPDATE SET col1 = t.col1, col2 = t.col2, ... col50 = t.col50 WHEN NOT MATCHED THEN INSERT (col1, col2, ... col50) VALUES (t.col1, t.col2, ... t.col50) The script runs all the way to the

Hi I have an interesting problem. I Have an Employee Table AS Follows CREATE TABLE EMPLOYEE( EMPLOYEE_ID INTEGER, SALARY DECIMAL(18,2), PAY_PERIOD DATE) Now the tables have employees some of whom get paid monthly,some weekly, some biweekly and some daily. What we want is to find an Indicator saying 'Y' if the salary of three consecutive Pay Periods is equal. Lets take the following example. Employee Pay_Period Salary 1 01/01/2012 $500 1 08/01/2012 $200 1 15/01/2012 $200 1 22/01/2012 $200 1 29/01/2012 $700 In this case the indicator should be Yes because 3 consecutive pay periods have a salary

I have been working ot see the equivalent function for Oracle lead and lag function. The oracle lead would look like LEAD(col1.date,1,ADD_MONTHS(col1.DATE,12)) OVER(Partition By tab.a,tab.b,tab.c Order By tab.a)-1 END_DATE LAG(col1.DATE + 7,1,col1.DATE-1) OVER(partition by tab.a,tab.b Order By tab.b) LAG_DATE Any better idea I believe you can take the following SQL as a basis and modify it to meet your needs: SELECT CALENDAR_DATE , MAX(CALENDAR_DATE) OVER(PARTITION BY 1 ORDER BY CALENDAR_DATE ROWS BETWEEN 1 PRECEDING AND 1 PRECEDING) AS Lag_ --Yesterday , MIN(CALENDAR_DATE) OVER(PARTITION BY 1