Temporal

See if the current time falls within a specific range of time in the current day in Java

旧巷老猫 提交于 2019-11-29 06:26:17
I am sure this was done 1000 times in 1000 different places. The question is I want to know if there is a better/standard/faster way to check if current "time" is between two time values given in hh:mm:ss format. For example, my big business logic should not run between 18:00:00 and 18:30:00 . So here is what I had in mind: public static boolean isCurrentTimeBetween(String starthhmmss, String endhhmmss) throws ParseException{ DateFormat hhmmssFormat = new SimpleDateFormat("yyyyMMddhh:mm:ss"); Date now = new Date(); String yyyMMdd = hhmmssFormat.format(now).substring(0, 8); return(hhmmssFormat

Rules engine for spatial and temporal reasoning?

浪尽此生 提交于 2019-11-29 05:19:55
I have an application that receives a number of datums that characterize 3 dimensional spatial and temporal processes. It then filters these datums and creates actions which are then sent to processes that perform the actions. Rinse and repeat. At present, I have a collection of custom filters that perform a lot of complicated spatial/temporal calculations. Many times as I discuss my system to individuals in my company, they ask if I'm using a rules engine. I have yet to find a rules engine that is able to reason well temporally and spatially. (Things like: When are two 3D entities ever close?

如何优雅的设计一个告警系统?远没有你想的那么简单

左心房为你撑大大i 提交于 2019-11-29 04:19:59
告警的本质 告警对象 监控的指标和策略 理论与现实 异常检测 基于曲线的平滑性检测 基于绝对值的时间周期性 基于振幅的时间周期性 基于曲线回升的异常判断 核心要点总结 告警的本质 没有多少系统的告警是设计得当的。良好的告警设计是一项非常困难的工作。 如何知道你收到的告警是糟糕的?多少次你收到了告警之后,立即就关掉了的?是不是成天被这些没有什么卵用的东西给淹没? 最常见的告警设置:cpu使用率超过90%,然后告警。这种设置在大部分场合下是没有办法提供高质量的告警的。 高质量的告警应该是这样的:每次收到之后你可以立即评估影响的范围,并且每一个告警需要你做出分级响应。所谓每个告警都应该是,actionable的。 告警的实质可以用下图表明: 服务器的设计应该是以这样的无人值守为目的的。假设所有的运维全部放假了,服务也能7*24自动运转。 告警的实质就是“ 把人当服务用 ”。在一些事情还没有办法做到程序化执行的时候,用告警通知人的方式去干预系统达到修正的目的。 一次告警就像一次服务调用一样。如果告警了,但是收到告警的人并不需要做任何处理,那么这就是一种DDoS攻击,攻击的是运维的幸福生活。 很多时候,告警通知人去干的事情是真的可以被自动化掉的。比如服务器挂了,换一台上来。 在小一点的系统里,可能就是停机一会,人工来处理换一台冷备的机器上去。 大一点的系统,因为服务器多了,天天都挂可不行

java8 LocalDateTime 工具类

喜你入骨 提交于 2019-11-28 10:32:18
参考链接1: java8时间类LocalDateTime 参考链接2: 如何在Java 8中愉快地处理日期和时间 参考链接3: Java Date Time - Custom Date Format Patterns import java.time.DayOfWeek; import java.time.Duration; import java.time.LocalDate; import java.time.LocalDateTime; import java.time.LocalTime; import java.time.Period; import java.time.format.DateTimeFormatter; import java.time.temporal.Temporal; import java.time.temporal.TemporalAdjuster; import java.time.temporal.TemporalAdjusters; public class DateTimeUtils { public static final DateTimeFormatter DATETIME_FORMATTER = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss"); public static

Rules engine for spatial and temporal reasoning?

妖精的绣舞 提交于 2019-11-27 23:03:11
问题 I have an application that receives a number of datums that characterize 3 dimensional spatial and temporal processes. It then filters these datums and creates actions which are then sent to processes that perform the actions. Rinse and repeat. At present, I have a collection of custom filters that perform a lot of complicated spatial/temporal calculations. Many times as I discuss my system to individuals in my company, they ask if I'm using a rules engine. I have yet to find a rules engine

Seed data with old dates in Temporal Table - SQL Server

末鹿安然 提交于 2019-11-27 18:29:16
问题 I need to seed data for my local development purpose in the following Temporal Table, the start date should be old. The given Table Schema is CREATE TABLE [dbo].[Contact]( [ContactID] [uniqueidentifier] NOT NULL, [ContactNumber] [nvarchar](50) NOT NULL, [SequenceID] [int] IDENTITY(1,1) NOT NULL, [SysStartTime] [datetime2](0) GENERATED ALWAYS AS ROW START NOT NULL, [SysEndTime] [datetime2](0) GENERATED ALWAYS AS ROW END NOT NULL, CONSTRAINT [PK_Contact] PRIMARY KEY NONCLUSTERED ( [ContactID]

日期和时间API

百般思念 提交于 2019-11-27 05:15:37
日期与时间 LocalDate 创建一个LocalDate对象并读取其值 // 根据年月日创建日期 LocalDate date1 = LocalDate.of(2014, 3, 18); // 读取 System.out.println(date1.getYear()); // 2014 System.out.println(date1.getMonth()); // MARCH System.out.println(date1.getMonth().getValue()); // 3 System.out.println(date1.getDayOfMonth()); // 18 System.out.println(date1.lengthOfMonth()); // 31 System.out.println(date1.isLeapYear()); // false // 当前日期 LocalDate now = LocalDate.now(); System.out.println(now); // 2018-08-14 // 从日期对象中获取年月日 System.out.println(now.get(ChronoField.YEAR)); // 2018 System.out.println(now.get(ChronoField.MONTH_OF_YEAR));