template-specialization

With regards to this question: How to create specialization for a single method in a templated class in C++? ... I have this class: template <typename T> class MyCLass { public: template <typename U> U myfunct(const U& x); }; // Generic implementation template <typename T> template <typename U> U MyCLass<T>::myfunct(const U& x) {...} And I want to specialize myfunct for double s. This is what I do: // Declaring specialization template <> template <typename T> double MyCLass<T>::myfunct(const double& x); // Doing it template <> template <typename T> double MyCLass<T>::myfunct(const double& x) {

I have a template class and a template member function: template<class T1> struct A{ template<class T2> static int f(){return 0;} }; I want to specialize for a case when T1 and T2 are the same, For example, define the case A<T>::f<T> for any T . but I can't find the combination of keywords to achieve this. How can I partially (?) specialize a combination of template class and a template static function? These are my unsuccessful attempts, and the error messages: 1) Specialize inside the class: fatal error: cannot specialize a function 'f' within class scope ) template<class T1> struct A{

In the code below, Foo<T>::setValue works well for my purposes, except in cases where where T is a class enum named TYPE e.g. Bar::TYPE and Baz:TYPE . Therefore, I'd appreciate help specializing Foo<T>::setValue without naming Bar and Baz , because there could be dozens of such classes. class Bar { public: enum TYPE{ ONE , TWO }; }; class Baz { public: enum TYPE{ SIX , TEN }; }; template<typename T> class Foo { public: void setValue(){} // Need a different setValue if T is a class enum private: T m_value; }; int main() { Foo<int> f1; Foo<Bar::TYPE> f2; Foo<Baz::TYPE> f3; return EXIT_SUCCESS; }