tasm

as per title, I know how to draw shape in 13h mode but have not idea how to move it on screen, next thing would be forcing the shape to bounce from edges of the screen, I think to redraw the shape in loop... but not to sure as I just started with assembly, I work on Tasm. Thanks for any suggestions. Not related to assembly at all. If you know how to draw shapes in 13h mode, just do the mental exercise. Imagine how the video memory (a000:0000 region) content looks when you draw the square at first position, then imagine the content of vram when the square is at second position. The difference

DOSSEG .MODEL SMALL .STACK 100h .DATA UserName db "Name: $" CLRF db 10,13,"$" inputName db 24 dup ("$") CurYear db "Current Year: $" inputCurrentYear dw 8 dup ("$") BirYear db "Birth Year: $" inputBirthYear dw 8 dup ("$") outputName db "Hello, $" outputAge db "Your age is $" currentYearH1 db "$" currentYearH2 db "$" birthYearH1 db "$" birthYearH2 db "$" answer1 dw "$" answer2 dw "$" .code BEGIN: ;open bracket mov ax,@data mov ds,ax mov es,ax mov al,03h mov ah, 00h int 10h lea dx,CLRF mov ah,09h int 21h ;username input NameInput: lea dx,UserName mov ah, 09h int 21h mov inputName,21 lea dx

We have given an instruction to make the the text CSC 112.1 to be centered. I used DB instruction and offset. This is my code .model small .stack .data c db 10,13,10,13," лллл ",10,13 db " лллллл ",10,13 db "лл лл",10,13 db "лл ",10,13 db "лл ",10,13 db "лл ",10,13 db "лл ",10,13 db "лл ",10,13 db "лл ",10,13 db "лл лл",10,13 db " лллллл ",10,13 db " лллл ",10,13,"$" .code mov ax,@data mov ds,ax call ccall ;call the procedure ccall which outputs C call scall ;call the procedure scall which outputs S call numcall ;call the procedure numcall which outputs 112.1 call exit ;call the procedure exit

SEG A : Assigns the content held in segment register corresponding to the segment in which A resides to the operand. I guess that means that if A lies in Data Segment, SEG A is the same as DS . Since DS holds the base address of the Data Segment, does MOV AX, LEA A MOV DX, SEG A MOV AX, [AX + DX] copy the physical address of A to AX ? I guess that means that if A lies in Data Segment, SEG A is the same as DS. Correct, if DS points to Data Segment. does MOV AX, LEA A MOV DX, SEG A MOV AX, [AX + DX] copy the physical address of A to AX? The last instruction is invalid, it does not exist in any

I need some help to understand what happens in the moment when this fragment of code "happens": "jmp Begin". I understand only that .com file can be 64kb so you want to put everything in one segment. You need to jmp if you want to put variables. But when I search about it, many guides just say in comment that jmp Begin is only to skip data and nothing else. And here is my question: What exactly happens in this moment: It appears that it runs this mov al, a mov bl, b sub al, bl But I can't understand why it looks like this in turbo debugger. When I change starting value of Result from ? to