syntax-error

Syntax error on tokens [duplicate]

◇◆丶佛笑我妖孽 提交于 2019-11-26 17:22:24
问题 This question already has an answer here: Unknown error relating to syntax of tokens 1 answer I am getting an error which i don't understand: Multiple markers at this line - Syntax error on token(s), misplaced construct(s) - Syntax error on tokens, delete these tokens The following is my code for the class, error occurs in line 8 (marked): import java.util.*; public class stringCalculator { String operator_array[] = {"+", "-", "/", "*", "(", ")"}; Queue<Integer> outputQueue = new LinkedList

Why isn't “0f” treated as a floating point literal in C++?

廉价感情. 提交于 2019-11-26 17:11:16
问题 Why isn't 0f treated as a floating point literal in C++? #include <iostream> using namespace std; int main(){ cout << 0f << endl; return 0; } Compiling the above gives me C2509 (syntax error: 'bad suffix on number') using VS2008. 回答1: If there was an explicitly stated reason for this design decision, it would be in the C99 "Rationale" document (C++ copied all this stuff verbatim from C without reconsidering it). But there isn't. This is everything that's said about the 'f' suffix: §6.4.4.2

Chrome: Uncaught SyntaxError: Unexpected end of input

馋奶兔 提交于 2019-11-26 17:09:47
When loading my page in Google Chrome, I get a vague error in the console: Uncaught SyntaxError: Unexpected end of input I have no idea what is causing it. How would I go about debugging this error? Ivo Wetzel This particular error is one annoying fact about v8 . In most cases your JavaScript is broken in some way. For example missing a } or something like that. Example given, this will yield "Unexpected end of input" too: eval('[{"test": 4}') // notice the missing ] But the root cause of the problems seems to be that the requested JSON url has a Content-Type of text/html which Chrome

Ternary Operators in JavaScript Without an “Else”

*爱你&永不变心* 提交于 2019-11-26 17:09:10
I've always had to put null in the else conditions that don't have anything. Is there anyway around it? E.g. condition ? x = true : null; basically, is there a way to do: condition ? x = true; Now it shows up as a syntax error FYI, here is some real example code: !defaults.slideshowWidth ? defaults.slideshowWidth = obj.find('img').width()+'px' : null; Sean Kinsey First of all, a ternary expression is not a replacement for an if/else construct - its an equivalent to an if/else construct that returns a value. That is, an if/else clause is code, a ternary expression is an expression , meaning

Ruby Block Syntax Error [duplicate]

妖精的绣舞 提交于 2019-11-26 15:32:25
Possible Duplicate: Ruby block and unparenthesized arguments I'm not sure I understand this syntax error. I'm using Carrierwave to manage some file uploads in a Rails app, and I seem to be passing a block to one of the methods incorrectly. Here's the example in the Carrierwave Docs : version :thumb do process :resize_to_fill => [200,200] end Here's what I had: version :full { process(:resize_to_limit => [960, 960]) } version :half { process(:resize_to_limit => [470, 470]) } version :third { process(:resize_to_limit => [306, 306]) } version :fourth { process(:resize_to_limit => [176, 176]) }

PHP syntax error “unexpected $end”

旧城冷巷雨未停 提交于 2019-11-26 14:49:32
问题 I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:<

Why doesn&#39;t 2.__add__(3) work in Python?

时光总嘲笑我的痴心妄想 提交于 2019-11-26 14:42:14
问题 The integer 2 has an __add__ method: >>> "__add__" in dir(2) True ... but calling it raises a SyntaxError: >>> 2.__add__(3) File "<stdin>", line 1 2.__add__(3) ^ SyntaxError: invalid syntax Why can't I use the __add__ method? 回答1: 2. is parsed as a float, so 2.__add__ is a SyntaxError. You can evaluate (2).__add__(3) instead. In [254]: (2).__add__(3) Out[254]: 5 回答2: Another way to get around 2. being parsed as a float is to insert a space between the 2 and the . >>> 2 .__add__(3) 5 来源: https

mysql error &#39;TYPE=MyISAM&#39;

巧了我就是萌 提交于 2019-11-26 13:47:59
问题 Below query I'm executing in Ubuntu 12, MySQL 5.1 version and receiving error as mentioned: CREATE TABLE mantis_config_table ( config_id VARCHAR(64) NOT NULL, project_id INTEGER NOT NULL DEFAULT 0, user_id INTEGER NOT NULL DEFAULT 0, access_reqd INTEGER DEFAULT 0, type INTEGER DEFAULT 90, value LONGTEXT NOT NULL, PRIMARY KEY (config_id, project_id, user_id) ) TYPE=MyISAM; You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax

Why does Eclipse complain about @Override on interface methods?

淺唱寂寞╮ 提交于 2019-11-26 12:58:08
I have an existing project that uses @Override on methods that override interface methods, rather than superclass methods. I cannot alter this in code, but I would like Eclpse to stop complaining about the annotation, as I can still build with Maven. How would I go about disabling this error? Note: Due to project requirements, I need to compile for Java 1.5. Using the @Override annotation on methods that implement those declared by an interface is only valid from Java 6 onward. It's an error in Java 5. Make sure that your IDE projects are setup to use a Java 6 JRE, and that the "source

How to correct TypeError: Unicode-objects must be encoded before hashing?

泄露秘密 提交于 2019-11-26 12:57:54
I have this error: Traceback (most recent call last): File "python_md5_cracker.py", line 27, in <module> m.update(line) TypeError: Unicode-objects must be encoded before hashing when I try to execute this code in Python 3.2.2 : import hashlib, sys m = hashlib.md5() hash = "" hash_file = input("What is the file name in which the hash resides? ") wordlist = input("What is your wordlist? (Enter the file name) ") try: hashdocument = open(hash_file, "r") except IOError: print("Invalid file.") raw_input() sys.exit() else: hash = hashdocument.readline() hash = hash.replace("\n", "") try: wordlistfile