syntax-error

Why is this function invalid? def request(method='get',resource, meta={}, strip=true) end unexcpected ')' expecting keyword_end Thank you! In Ruby, you can't surround a required parameter with optional parameters. Using def request(resource, method='get', strip=true, meta={}) end will solve the issue. As a thought experiment, consider the original function def request(method='get',resource, meta={}, strip=true) end If I call that method as request(object) , the desired behavior is fairly obvious -- call the method with object as the resource parameter. But what if I call it as request('post',

The integer 2 has an __add__ method: >>> "__add__" in dir(2) True ... but calling it raises a SyntaxError: >>> 2.__add__(3) File "<stdin>", line 1 2.__add__(3) ^ SyntaxError: invalid syntax Why can't I use the __add__ method? 2. is parsed as a float, so 2.__add__ is a SyntaxError. You can evaluate (2).__add__(3) instead. In [254]: (2).__add__(3) Out[254]: 5 Another way to get around 2. being parsed as a float is to insert a space between the 2 and the . >>> 2 .__add__(3) 5 来源： https://stackoverflow.com/questions/13390458/why-doesnt-2-add-3-work-in-python

In a Python script I call a function from rpy2 , but I get this error: #using an R module res = DirichletReg.ddirichlet(np.asarray(my_values),alphas, log=False, sum.up=False) SyntaxError: keyword can't be an expression What exactly went wrong here? sum.up is not a valid keyword argument name. Keyword arguments must be valid identifiers. You should look in the documentation of the library you are using how this argument really is called – maybe sum_up ? I guess many of us who came to this page have a problem with Scikit Learn, one way to solve it is to create a dictionary with parameters and

This question already has an answer here: PHP Error : Fatal error: Constant expression contains invalid operations 4 answers I have the following code, where I get the error "PHP Fatal Error: Constant expression contains invalid operations". It works fine when I define the variable in the constructor. I am using Laravel framework. <?php namespace App; class Amazon { protected $serviceURL = config('api.amazon.service_url'); public function __construct() { } } As described here Class member variables are called "properties". You may also see them referred to using other terms such as "attributes

Below query I'm executing in Ubuntu 12, MySQL 5.1 version and receiving error as mentioned: CREATE TABLE mantis_config_table ( config_id VARCHAR(64) NOT NULL, project_id INTEGER NOT NULL DEFAULT 0, user_id INTEGER NOT NULL DEFAULT 0, access_reqd INTEGER DEFAULT 0, type INTEGER DEFAULT 90, value LONGTEXT NOT NULL, PRIMARY KEY (config_id, project_id, user_id) ) TYPE=MyISAM; You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'TYPE=MyISAM' at line 9 Can anyone suggest what's wrong? Replace TYPE=MyISAM with ENGINE

I get this PHP error: Parse error: syntax error, unexpected T_VARIABLE From this line: $list[$i][$docinfo['attrs']['@groupby']] = $docinfo['attrs']['@count']; Is there anything wrong with this line? knittl There might be a semicolon or bracket missing a line before your pasted line. It seems fine to me, every string is allowed as array index. dusoft It could be some other line as well, PHP is not always that exact. Probably you are just missing a semicolon on previous line. How to reproduce this error, put this in a file called a.php : <?php $a = 5 $b = 7; //error happens here. print $b; ?>