syntax-error

问题 I´m trying to get a simple TypeScript file working in PHPStorm, but sadly there seem to be some misconfiguration by default as the class keyword is not recognized properly This is my TypeScript file: class Test{ } And this is the error I´m facing: And this is my FieWatcher configuration of TypeScript How can I get TypeScript working? 回答1: The Program options should not be node.exe (that would mean you are trying to typescript code as javascript). It needs to be tsc or node tsc (that means you

问题 I have a little problem of not being abble to retrieve csv response. There is a csv available here link to csv I am trying to retrieve this data, however there is a problem with special characters in the reponse. I successfuly recieve the data but then jQuery tries to decode it and through a syntax error: My request is: $.ajax({ url: 'http://toolserver.org/~daniel/WikiSense/Contributors.php?wikilang=en&wikifam=.wikipedia.org&page=Cloud+computing&since=&until=&grouped=on&order=-edit_count&max

问题 I'm working on a program that is supposed to put every Window in a list, resize it, and move it to a screen position according to a specified layout. When I'm running this function however I get a debug assertion error saying "list iterators incompatible". Here is the code: void Control::checkForNewWindows() { for (std::list<Window>::iterator i = mainDetector.getWindowList().begin(); i != mainDetector.getWindowList().end(); ++i) { bool forBreak = false; if ((i->getTitle().find("sample_title")

问题 I was having a bit of trouble with this code that I wrote in Python 2.7. It's giving me a syntax error on the elif statement, but there's no explanation and I can't find any reasonable error in the code. (typeline is a method I defined.) num = randrange(-25,15) """ Toxic """ if num >= -25 and num < -10: responses = ["Ugh, nasty.", "That was absolutely disgusting.", "My stomach feels like it's going to explode.", "Pardon me if I puke."] typeline(responses[randrange(0,4)], "jack") return [num,

问题 I am trying to find the minimum value of a list (as a learning experience, so without min ). My approach is the following: minimo([X], X). minimo([X,Y|Tail], N):- (X > Y, minimo([Y,Tail], Y)); (X <= Y, minimo([X,Tail], X)). This gives me the following error: Syntax error: Operator expected So my questions are: What is causing the syntax error? I will try it myself once that is fixed if it actually gives the correct value back, but would this actually be a correct approach? Thanks in advance.

问题 The Background Each month I run a crosstab query which is then "spruced up" with an Access Report. CROSSTAB SQL: TRANSFORM Sum(myTable.Field1) AS SumOfField1 SELECT myTable.Date, Sum(myTable.Field1) AS [Daily Totals] FROM myTable GROUP BY myTable.Date PIVOT myTable.Field2; where Field1 is a $ Amount, and Field2 (for this example) is either going to be "Option1", "Option2", or "Option3". TYPICAL CROSSTAB RESULTS: Date Option1 Option2 Option3 ----- -------- -------- -------- Day1 $5.00 -$2.37

问题 I need some help in this SQL Code. I am new to SQL and using the Sams Teach Yourself SQL. INSERT INTO `eli`.`checks` (`check`, `payee`, `amount`, `remarks`) VALUES (500,'John Dree',450.00,'Bills'); INSERT INTO `eli`.`checks` (`check`, `payee`, `amount`, `remarks`) VALUES (575,'Ma Belle',150.00,'Gas Bills'); INSERT INTO `eli`.`checks` (`check`, `payee`, `amount`, `remarks`) VALUES (600,'Jon Cash',350.00,'Shopping'); I am getting error 1064: . You have an error in your SQL syntax; check the

问题 This question already has answers here : Python not equal operator (4 answers) Closed 3 years ago . I'm trying to do this assignment: This is what I have and I am getting a syntax error on > Pasted code: # Specify where the input and output file is InputFile = open('C:\Python\unsorted_fruits.txt', 'r') OutputFile = open('C:\Python\sorted_fruits.txt', 'w') # Read the input file Fruits = InputFile.readlines() # Sort the items in the list Fruits.sort() # Remove the blank lines and write the file

问题 this is the class i am using public class ContactsXmpp extends SherlockFragmentActivity { private static Context ctx; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.contacts_xmpp_sip); ctx = this; } i am getting error when i call asynctask from this method. this is the error No enclosing instance of type ContactsXmpp is accessible. Must qualify the allocation with an enclosing instance of type ContactsXmpp (e.g. x.new A(

问题 $query = "SELECT a.*, cc.name AS category, dd.ezcity AS proploc, ee.name AS statename, ff.name AS cnname, ss.dealer_name AS propseller, u.name AS editor" . "\n FROM #__ezrealty AS a" . "\n LEFT JOIN #__ezrealty_catg AS cc ON cc.id = a.cid" . "\n LEFT JOIN #__ezrealty_locality AS dd ON dd.id = a.locid" . "\n LEFT JOIN #__ezrealty_state AS ee ON ee.id = a.stid" . "\n LEFT JOIN #__ezrealty_country AS ff ON ff.id = a.cnid" . "\n LEFT JOIN #__ezrealty_profile AS ss ON ss.mid = a.owner" . "\n LEFT