syntax-error

问题 I want to use CASE in my stored procedure. I am getting some syntax error in my code: select case @Temp when 1 then (@selectoneCount=@selectoneCount+1) when 2 then (@selectoneCount=@selectoneCount+1) end When running, I'm getting: incorrect syntax near '='. at this line here: @selectoneCount = @selectoneCount + 1 near the equal. Actually I am getting return value from a another sp into @temp and then if @temp =1 then I want to increment the count of @SelectoneCount by 1 and so on. Please let

问题 I found this code here --> ::Check if the path is File or Folder using batch But I find it hard to read and want to simplify it/break it apart. I'm not sure how to do this, I tried the below and a few variations to no avail. Can anybody help? Thanks! This code works: @Echo Off Set "ATTR=D:\Download\Documents\New" For %%Z In ("%ATTR%") Do If "%%~aZ" GEq "d" (Echo Directory ) Else If "%%~aZ" GEq "-" (Echo File) Else Echo Inaccessible Pause This is what I would like it to look like, but can't

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . The nested if statement below is causing a syntax error and I can not see why. scores = [] choice = None while choice != 0: print( """ High Scores 0 - Exit 1- Show Scores 2- Add a Score 3 -Delete a Score 4- Sort Scores """ ) #take use input choice = input("Choice:") if choice == 0: print ("Good Bye") elif choice

问题 This question already has an answer here : ISO C++ forbids declaration of ‘multiset’ with no type (1 answer) Closed 4 years ago . I am trying to build a software using waf and I get the error: In file included from ../src/internet-stack/mp-tcp-typedefs.cc:6: ../src/internet-stack/mp-tcp-typedefs.h:151: error: ISO C++ forbids declaration of ‘multiset’ with no type ../src/internet-stack/mp-tcp-typedefs.h:151: error: expected ‘;’ before ‘<’ token ../src/internet-stack/mp-tcp-typedefs.cc: In

问题 This question already has answers here : I keep getting an error next to the return VARCHAR(4) (2 answers) Closed 5 years ago . This has an error next to VARCHAR2 and (4) : CREATE OR REPLACE FUNCTION Employee_exists (p_employee_id IN NUMBER) RETURN VARCHAR2(4); AS BEGIN SELECT employee_id FROM employees WHERE employee_id = p_employee_id; RETURN 'true'; END Employee_exists; Here it says there is an error next to the decleration of v_years_service : CREATE OR REPLACE FUNCTION Calculate_Bonus(p

问题 In my C# application, I am using a MessageFilter for a global key hook as suggested by T Perquin. This is my current code: class KeyboardMessageFilter : IMessageFilter { public bool PreFilterMessage(ref Message m) { if (m.Msg == ((int)Helper.WindowsMessages.WM_KEYDOWN)) { switch ((int)m.WParam) { case (int)Keys.Escape: // Do Something return true; case (int)Keys.Right: // Do Something return true; case (int)Keys.Left: // Do Something return true; } } return false; } } When I try to compile

问题 I'm trying to see where a Python syntax error would be hiding. Both Django and pylint claim a syntax error at custom.py:41. Lines 41-42 read: (reading_threshold = int(request.POST['reading_threshold'])) I do not see anything that I can notice as wrong in that statement or the syntax in custom.py. What is my mistake here? A slightly sanitized version of the file reads: from django.http import HttpResponse def threshold_check(user, item, text = None): if user.issuperuser(): if text == None:

问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 6 years ago . code: public function isQuestion($query){ $questions = $this->getAllQuestions(); if (count($questions)){ foreach ($questions as $q){ if ($this-

问题 Is it me or the interpreter? I see no indentation error in my code but it kept telling me that there is an error! I use auto indentation so it should be ok. When ever there is an indentation error, I backspace then indent again and it seems to fix it because the indentation error is not on that line anymore but on the other line. Can someone please tell me what is wrong class LogicGate: def __init__(self,n): self.label = n self.output = None def getLabel(self): return self.label def getOutput

问题 Can someone help me find the error in my program? When I compile it, it gives the cannot find symbol error. I have been playing around with it for a while but cant seem to grasp my mistake. My main class: public static void main(String[] args) { int plays; SlotMac machine[] = new SlotMac[3]; machine[0] = new SlotMac(3,35,30); machine[1] = new SlotMac(10,100,60); machine[2] = new SlotMac(4,10,9); plays= firstmachine(machine[0]); System.out.println(plays); My other class: public class SlotMac {