syntax-error

问题 Just wondering if anyone knows how to fix this error? I've also used TypeCode. but still no luck. Thanks case typeof(Nullable<int>).ToString(): //<----- error is here if ((!object.ReferenceEquals(value, DBNull.Value))) { return value; } else { return null; } This is the switch public static object HandleDBNull(object value, System.Type _type) { switch (Type.GetTypeCode(_type)) { Thanks again for any help 回答1: Ultimately, typeof(Nullable<int>) isn't a TypeCode , and the string representation

问题 I've been using as.formula for setting up a glm, and I can't figure out where the unexpected symbol is. Part of the problem is that the character vector I'm converting is so long. It's about 700 words with + inserted in between in order to turn it into a formula. The error presents as follows: Error in parse(text = x, keep.source = FALSE) : <text>:2:10080: unexpected symbol with the following snippet of the text: 2: c_1_E + Campaign_Search_Payroll_Generic_1_P + Campaign_Search_Performing_Core

问题 I just trying to use a update in my application, but i just can't. A the console, this mysql command works, but here, doesn't. Well, I use this in my program: conexao = poolMySQL.connect(); final String sql = "UPDATE professor SET codlocal = ? WHERE codprof = ?"; pstmt = conexao.prepareStatement(sql); pstmt.setInt(1, local); pstmt.setInt(2, id); try { pstmt.executeUpdate(sql); } catch (SQLException ex) { Logger.getLogger(ProfessorDAO.class.getName()).log(Level.SEVERE, null, ex); } Just

问题 What is happening here? I got two tables, test1 and test2: create table test1 (id1 int4 primary key); create table test2 (id2 int4 primary key); As expected, this query: select id1 from test2; produces a syntax error: ERROR: column "id1" does not exist LINE 1: select id1 from test2; However, when I try to execute this query: select * from test1 where id1 in (select id1 from test2); PostgreSQL doesn't complain, executes the query and gives me: id1 ----- (0 rows) Is there any logic in this? Or

问题 I am trying to get this to work: echo "Would you like to configure dns?" select yn in "Yes" "No"; do case $yn in Yes ) echo "you have selected to configure dns"; break;; No ) exit; break;; esac done I keep getting this error: menu.sh: 2: select: not found menu.sh: 7: Syntax error: "done" unexpected Thanks in Advance, joe 回答1: Make sure you are running it in bash as select is understood by bash and not by some shells like sh . 回答2: Alternatively, just rewrite using while , read and case . I

问题 I have this code: $.ajax({ dataType: 'text', url: '/_/js/answers.json', type: "GET", success: function (data) { alert(data); alert(data.code); var result = JSON.parse(data); var hey = JSON.parse('{"code": 123}'); alert(hey.code); alert(result.code); }, error: function () { alert("code not found"); } }); In the first alert, alert(data) it shows me '{"code": 123}', in the second alert alert(data.code) , it tells me undefined , in the third alert alert(hey.code) , it shows me 123 , and that's

问题 I'm new to VBA, and I'd like to use it to do some difficult and arduous tasks. I have a large amount of Excel files with thousands of rows and several columns. I need to search, by row, and extract certain cells with specific strings. I've pieced together some functions and code and I have almost got it to work but I keep getting unexpected results like irrelevant data being extracted or it random errors because I don't understand VBA syntax super well. As a newbie to Excel, I'm at my wits

问题 This question is very much like: if/else in Python's list comprehension? and Simple syntax error in Python if else dict comprehension . But still i dont understand what error I make here: [i if i!=0 for i in range(2)] ^ syntax error I only want the entries in the list that are non-zero for sparsity. 回答1: Move the if to the end. Refer to The Python Docs entry on List Comprehensions. >>> [i for i in range(2) if i!=0] # Or [i for i in range(2) if i] [1] If you were looking for a conditional

问题 r'\' in Python does not work as expected. Instead of returning a string with one character (a backslash) in it, it raises a SyntaxError. r"\" does the same. This is rather cumbersome if you have a list of Windows paths like these: paths = [ r'\bla\foo\bar', r'\bla\foo\bloh', r'\buff', r'\', # ... ] Is there a good reason why this literal is not accepted? 回答1: This is in accordance with the documentation: When an 'r' or 'R' prefix is present, a character following a backslash is included in

问题 I am still working on an iPhone app called Cruzia and am now wondering why I am geting these two warnings, both in ViewController.m and three errors, all an Apple Mach-O Linker Error. If you can point me in the direction of some fixes I would be very appreciative. I have commented the warnings out below in a copy of my viewcontroller.m: #import "CIAViewController.h" @interface CIAViewController() @end @implementation CIAViewController -(IBAction)press { cruzia.hidden = 0; textarea.hidden = 0;