syntax-error

Javascript error; Uncaught SyntaxError: missing ) after argument list

◇◆丶佛笑我妖孽 提交于 2019-12-30 17:25:24
问题 I keep getting this error (Javascript error; Uncaught SyntaxError: missing ) after argument list) when trying to call a simple function. Everything works without calling it in a function but I need to do it multiple times. function myFunction(ip, port, div) { $.get('http://mcping.net/api/'+ ip + ":" + port, function(data){ console.log(data.online); $(div).html(data.online); }); } myFunction(162.223.8.210, 25567, #factionsOnline) 回答1: You're missing a parentheses because you didn't quote your

MySQL server stored procedure syntax error

半腔热情 提交于 2019-12-29 09:21:27
问题 I am having some trouble with creating a Stored Procedure for a MySQL database. Here is a Select statement that works: use canningi_db_person_cdtest; SELECT * FROM pet WHERE name = 'Puffball'; Here is my Stored Procedure that does not work: use canningi_db_person_cdtest; CREATE PROCEDURE GetAllPets() BEGIN SELECT * FROM pet WHERE name = 'Puffball'; END I am getting the following error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version

MySQL server stored procedure syntax error

ⅰ亾dé卋堺 提交于 2019-12-29 09:21:26
问题 I am having some trouble with creating a Stored Procedure for a MySQL database. Here is a Select statement that works: use canningi_db_person_cdtest; SELECT * FROM pet WHERE name = 'Puffball'; Here is my Stored Procedure that does not work: use canningi_db_person_cdtest; CREATE PROCEDURE GetAllPets() BEGIN SELECT * FROM pet WHERE name = 'Puffball'; END I am getting the following error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version

Mysql syntax seems correct

我们两清 提交于 2019-12-29 09:17:08
问题 So... I received: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key = '48f9f4a3f5e10c63804400f320f46e26'' at line 1 and so I reflected it back to myself, on the webpage and it reads: SELECT * FROM email_confirm WHERE email = 'censored@gmail.com' AND key = '48f9f4a3f5e10c63804400f320f46e26' I don't see the issue. MySQL version is 5.1.65-cll Answer: KEY is a reserved word in mysql. Need backticks ! 回答1: key

Python - I can't see my what my error is because the window disappears immediately

筅森魡賤 提交于 2019-12-29 02:07:44
问题 I am pretty new to Python and I have been pretty annoyed with this problem. I am not sure if this matters, but I run my .py file with Python 2.7.6 with python installed on my computer, not using it on any online thing or other program. Every time I come across an error, my program works fine until it comes to the error, but the window disappears right before I can possibly read whatever the error said it was... Anyways, I haven't been able to find out what is wrong with my programming, and I

Python - I can't see my what my error is because the window disappears immediately

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-29 02:07:20
问题 I am pretty new to Python and I have been pretty annoyed with this problem. I am not sure if this matters, but I run my .py file with Python 2.7.6 with python installed on my computer, not using it on any online thing or other program. Every time I come across an error, my program works fine until it comes to the error, but the window disappears right before I can possibly read whatever the error said it was... Anyways, I haven't been able to find out what is wrong with my programming, and I

PHP 5.4 vs 5.3 app errors

混江龙づ霸主 提交于 2019-12-28 02:18:33
问题 I am building an web app with php and built it in php 5.4. However, I just realized my server run only 5.3 or 5.2. In my controller file I have this line of code $this->load->model('admin/upholstery_category_admin'); $this->load->helper('url'); if($method == 'add') { $categories = $this->db->get('category')->result(); line 158 here>> $data = []; $data['cats'] = $categories; $data['message'] = ''; which is causes this error Parse error: syntax error, unexpected '[' in /home/content/51/6663351

calling function inside preg_replace thats inside a function

大憨熊 提交于 2019-12-28 01:27:46
问题 I have some code with the a structure similar to this function bbcode($Text) { //$Text = preg_replace("/\[video\](.+?)\[\/video\]/",embed_video($1), $Text); return $Text;} function embed_video($url){ if (preg_match("/http:\/\/www.youtube.com\/watch\?v=([0-9a-zA-Z-_]*)(.*)/i", $url, $matches)) { return '<object width="425" height="350">'. '<param name="movie" value="http://www.youtube.com/v/'.$matches[1].'" />'. '<param name="wmode" value="transparent" />'. '<embed src="http://www.youtube.com

Chrome: Uncaught SyntaxError: Unexpected end of input

大兔子大兔子 提交于 2019-12-27 11:51:13
问题 When loading my page in Google Chrome, I get a vague error in the console: Uncaught SyntaxError: Unexpected end of input I have no idea what is causing it. How would I go about debugging this error? 回答1: This particular error is one annoying fact about v8. In most cases your JavaScript is broken in some way. For example missing a } or something like that. Example given, this will yield "Unexpected end of input" too: eval('[{"test": 4}') // notice the missing ] But the root cause of the

Cannot find symbol from ResultSet JDBC [duplicate]

二次信任 提交于 2019-12-26 14:36:45
问题 This question already has answers here : What does a “Cannot find symbol” or “Cannot resolve symbol” error mean? (13 answers) Closed 7 months ago . I'm getting a cannot find symbol error and it points to the period right in rs.getChars(1) This code is all within a try{} . There are three columns in the view table, title, item_id, and name. I'm just trying to query it but get a cannot find symbol on the line inside the start of the while loop. PreparedStatement pstmt= conn.prepareStatement(