switch-statement

问题 So I am creating a video game where an icon moves with pc controllers. Also, I want that when I press the space bar, my icon (spaceship which moves with controllers) switches between styles. I have manged to do that but it only works one time and I can't go back to the initial image. What I would like to have would be that it switches between four images and at the end of it returns to the original style. Here is the code for controllers: let display = document.getElementById("body").style

问题 I want to write a function with a switch statement to count the number of occurrences of any two vowels in succession in a line of text. For example, in the sentence For example: Original string = “Pl ea ses r ea d this application and give me grat ui ty”. Such occurrences in string ea, ea, ui. Output: 3 function findOccurrences() { var str = "Pleases read this application and give me gratuity"; var count = 0; switch (str) { case 'a': count++; case 'A': count++ case 'e': case 'E': case 'i':

问题 I want to write a function with a switch statement to count the number of occurrences of any two vowels in succession in a line of text. For example, in the sentence For example: Original string = “Pl ea ses r ea d this application and give me grat ui ty”. Such occurrences in string ea, ea, ui. Output: 3 function findOccurrences() { var str = "Pleases read this application and give me gratuity"; var count = 0; switch (str) { case 'a': count++; case 'A': count++ case 'e': case 'E': case 'i':

问题 Following is the excerpt from Dennis M Ritchie's book, ANSI C: Each case is labeled by one or more integer-valued constants or constant expressions. I could not come up with an example of a switch case where we have case with more than one label . Any example illustrating the above property will be helpful. 回答1: Here's an example I found in a program which checks options: switch (optionChar) { case 'a': case 'A': case 'f': case 'F': case 'q': case 'Q': case 'z': case 'Z': optionsOk = TRUE;

问题 This will mostly get duplicated but I sincerely don't know how to search this question since it is too long and complicated. Sorry in advance! Back to the problem, let's say I take an input from the user with the Scanner class. Imagine that Scanner is imported and everything is set. Scanner scan = new Scanner(); String input = scan.nextLine(); switch( input) { case "attack": System.out.println( "You attacked the enemy!"); break; case "defend": System.out.println( "You blocked the enemy!");

问题 I am trying to make a door relay switch system that i am able to operate from anywhere via port forwarding. I have found a very helpfull guide and code where i based my program on: https://openhomeautomation.net/control-a-lamp-remotely-using-the-esp8266-wifi-chip https://github.com/openhomeautomation/esp8266-relay I made the code a little different to reset the esp8266 after five seconds of putting the relay in high state. That all worked fine but when i accessed the port via multiple devices

问题 This question already has answers here : What is “…” in switch-case in C code (4 answers) Closed 4 years ago . Is '...' symbol is a c language keyword? The code: #include <stdio.h> typedef enum { A=0,B,C,D,E,F,G,H,I,J,K,M } alpha; int main(int argc, char const *argv[]) { alpha table = C; switch (table) { case A ... D: /* I have never seen "..." grammar in textbook */ printf("Oh my god\n"); break; default: printf("default\n"); break; } return 0; } Is ... allowed in C for range? 回答1: It's not

问题 This question already has answers here : What is “…” in switch-case in C code (4 answers) Closed 4 years ago . Is '...' symbol is a c language keyword? The code: #include <stdio.h> typedef enum { A=0,B,C,D,E,F,G,H,I,J,K,M } alpha; int main(int argc, char const *argv[]) { alpha table = C; switch (table) { case A ... D: /* I have never seen "..." grammar in textbook */ printf("Oh my god\n"); break; default: printf("default\n"); break; } return 0; } Is ... allowed in C for range? 回答1: It's not

问题 This question already has answers here : Java switch statement: Constant expression required, but it IS constant (13 answers) Closed 4 years ago . I was working on switch case. If we use class.getName(), then, I am getting error that "case expressions must be constant expressions" as follows: switch(param.getClass().getName()) { case String.class.getName(): // to do break; } Even if we do following, take string class name in a constant, then also, getting same error: public static final

问题 This question already has answers here : Java switch statement: Constant expression required, but it IS constant (13 answers) Closed 4 years ago . I was working on switch case. If we use class.getName(), then, I am getting error that "case expressions must be constant expressions" as follows: switch(param.getClass().getName()) { case String.class.getName(): // to do break; } Even if we do following, take string class name in a constant, then also, getting same error: public static final