switch-statement

问题 Before you start criticizing and pointing me §8.7.2 of C# specification, read carefully :) We all know how switch looks like in C#. Ok so consider the class MainWindow with "nasty" Bar method static int barCounter = 0; public static int Bar() { return ++barCounter; } Somewhere in this class we have code like this Action switchCode = () => { switch (Bar()) { case 1: Console.WriteLine("First"); break; case 2: Console.WriteLine("Second"); break; } }; switchCode(); switchCode(); In the console

问题 switch(at){ case (at>0 && at<5) : printf("Average Time Taken (Hrs)\n%d.0",at); printf("Your Salary is Rs.%d",pj*1500 + 5000); break; rest of the codes are similar. And i'm getting error for this case (at>0 && at<5) : 回答1: I'm afraid this is not possible. Quoting C11 , chapter §6.8.4.2 The expression of each case label shall be an integer constant expression and no two of the case constant expressions in the same switch statement shall have the same value after conversion. [....] so the case

问题 switch(at){ case (at>0 && at<5) : printf("Average Time Taken (Hrs)\n%d.0",at); printf("Your Salary is Rs.%d",pj*1500 + 5000); break; rest of the codes are similar. And i'm getting error for this case (at>0 && at<5) : 回答1: I'm afraid this is not possible. Quoting C11 , chapter §6.8.4.2 The expression of each case label shall be an integer constant expression and no two of the case constant expressions in the same switch statement shall have the same value after conversion. [....] so the case

问题 OK, so let's say I have this: $(function() { $('#good_evening').keyup(function () { switch($(this).val()) { case 'Test': // DO STUFF HERE break; } }); }); ... this would only run if you typed "Test" and not "test" or "TEST". How do I make it case-insensitive for JavaScript functions? 回答1: switch($(this).val().toLowerCase()) { case 'test': // DO STUFF HERE break; } 回答2: Why not lowercase the value, and check against lowercase inside your switch statement? $(function() { $('#good_evening')

问题 I have a situation where I would like for two cases in a C++ switch statement to both fall through to a third case. Specifically, the second case would fall through to the third case, and the first case would also fall through to the third case without passing through the second case. I had a dumb idea, tried it, and it worked! I wrapped the second case in an if (0) { ... } . It looks like this: #ifdef __cplusplus # include <cstdio> #else # include <stdio.h> #endif int main(void) { for (int i

问题 So first off, I'm completely brand new to Java and I know this is probably really easy for most of you. But right now I'm stuck with an exercise. I have googled almost frantically, but I can't find any helpful tips to this particular problem. That or I don't really know what to search for. I have a piece of code that looks like this: import java.util.Scanner; public class Week { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("Type a number:

问题 #include <iostream> using namespace std; int main() { int score; char grade; cout << "Enter your score:" << endl; cin >> score; if (score >= 90) grade = 'a'; if (score >= 80) grade = 'b'; if (score >= 70) grade = 'c'; if (score >= 60) grade = 'd'; else grade = 'f'; cout << grade << endl; switch (grade) { case 'a': cout << "Good job" << endl; break; case 'c': cout << "Fair job" << endl; break; case 'f': cout << "Failure" << endl; break; default: cout << "invalid" << endl; } cin.get(); return 0

问题 #include <iostream> using namespace std; int main() { int score; char grade; cout << "Enter your score:" << endl; cin >> score; if (score >= 90) grade = 'a'; if (score >= 80) grade = 'b'; if (score >= 70) grade = 'c'; if (score >= 60) grade = 'd'; else grade = 'f'; cout << grade << endl; switch (grade) { case 'a': cout << "Good job" << endl; break; case 'c': cout << "Fair job" << endl; break; case 'f': cout << "Failure" << endl; break; default: cout << "invalid" << endl; } cin.get(); return 0

问题 #include <iostream> using namespace std; int main() { int score; char grade; cout << "Enter your score:" << endl; cin >> score; if (score >= 90) grade = 'a'; if (score >= 80) grade = 'b'; if (score >= 70) grade = 'c'; if (score >= 60) grade = 'd'; else grade = 'f'; cout << grade << endl; switch (grade) { case 'a': cout << "Good job" << endl; break; case 'c': cout << "Fair job" << endl; break; case 'f': cout << "Failure" << endl; break; default: cout << "invalid" << endl; } cin.get(); return 0

问题 I'm new to python, and I'd like to create a switch case where the cases can have intervals as condition, like: switch = { 1..<21: do one stuff, 21...31: do another } How can I achieve this result? 回答1: As it looks like you already tried, the obvious way of implementing a switch structure in Python is using a dictionary. In order to support intervals , you could implement your own dict class: class Switch(dict): def __getitem__(self, item): for key in self.keys(): # iterate over the intervals