switch-statement

问题 I am working on a php code as shown below on which Line#A prints the following array (shown below php code). My code doesn't seems to go inside switch statement. I am not sure why. I added print_r($parts) at Line A in order to print the value of $parts. php code: <?php if (!empty($_POST['id'])) { for($i=0; $i <count($mp4_files); $i++) { if($i == $_POST['id']) { $f = $mp4_files[$i]; $parts = pathinfo($f); print_r($parts); // Line A switch ($parts['extension']) { echo "Hello World"; // Line B

问题 My object randomised spawn code always sets a weapons damage to the same number every time I run the code. Although it sometimes changes between 3 (for daggers), 4, 6 and 8, but every item's damage on the map is the same. I thought it might be because there were no breaks back when I had returns at the end of each case however this wasn't the 'case' and still only outputs the same few damages. Example screenshot of all the sword damages as 4: http://puu.sh/hevSP/7974257751.png It's not the

问题 I am implementing some methods which use switch statements to distinguish between different cases: private void doThis(){ switch(command){ case on: {status = doCalculationsA; break;} case off: {status = doCalculationsB; break;} case idle: {status = doCalculationsC; break;} case stdby:{status = doCalculationsD; break;} } } The above works fine, when, further down the business logic, I call doThis() inside other methods which need the doThis() functionality. However, at this moment I am a bit

问题 I have an SSRS report where I'm supposed to conditionally format a column red/green depending on if an expression is +/- 5% (less is good, so less is green). I also need to have the entire report have alternating row highlighting. I can get these to function correctly until I throw in some NULL handling. =Switch ( IsNothing(Sum(Fields!August2015.Value)),IIf(RowNumber(Nothing) Mod 2 = 0, "#d9d9d9", "Transparent"), (Fields!August2015.Value-Fields!CorporateAvg.Value)/Fields!CorporateAvg.Value >=

问题 Is there a way I can generate switch statements in jquery/javascript by using some sort of loop to do the work for me? For example, if I had a statement like: switch ($("#play option:selected").text()) { case '1': $("#play_1").slideDown().find("input").addClass("someClass"); break; case '2': $("#play_1").slideDown().find("input").addClass("someClass"); $("#play_2").slideDown().find("input").addClass("someClass"); break; } This is fine if I only have a few options in my select menu, but what I

问题 Brief description So thanks to the svg-to-react-cli script I have 73 components for my icons. Now, if I want to call these icons, I can individually call each one I want to use. But this is not what I want. What I want is to call only one component where I add a 'name' value to. e.g.: < Icon name='Name of one of the 73 components I wish to call' /> My question How do I loop through multiple components inside a directory, and return them inside a switch case? This is how all my 73 components

问题 I've got code that looks like this: class Base { func launch(code1: Int, code2: Int) -> Bool { return false } } class A: Base {} class B: Base {} class C: Base {} func trynext(obj: Base) -> Base? { switch obj { case is A: return B() case is B: return C() default: return nil } } Basically, I've got a lot (like 20) of subclasses of a common base class and I need to go through them one by one. These subclasses represent parsers and I'm trying them one after another to discover which parser

问题 I am having trouble with the below switch statement: names <- rep(1:num.bins, 3) names <- sort(names) c.names <- sapply(1:(3*num.bins), function(i){ switch( i %% 3, 1 = paste0("M", names[i]), 2 = paste0("F", names[i]), 0 = paste0("E", names[i]) ) }) If my 'num.bins' is 3, I'd like the following output: print(names) [1] 1 1 1 2 2 2 3 3 3 print(c.names) [1] "M1" "F1" "E1" "M2" "F2" "E2" "M3" "F3" "E3" however, I'm getting an error. Thank you very much for your help. 回答1: You need to decide what

问题 I've got two SVN branches (eg development and stable) and want to switch from one to another... In every tutorial there is command like: rootOfLocalSvnCopy:>svn switch urlToNewBranch . But it leads in error in my case: svn: REPORT request failed on '/svn/rootOfLocalSvnCopy/!svn/vcc/default'<br/> svn: Cannot replace a directory from within Every help that I found is about svn switch --relocate but I don't want to relocate, just to change my working copy to another branch 回答1: OK, I get it work

问题 I have one single file called Exercises.rb def ask(prompt) print prompt, ' ' $stdout.flush s = gets return s end def myreverse(s) aux="" for i in 0..s.length-1 aux=s[i] + aux end return aux end def mywordreverse(s) aux=[] s=s.split(" ") for i in 0..s.length-1 aux.unshift(s[i]) end return aux.join(" ") end def choose(s,option) case option when 1 then print myreverse(s) when 2 then print mywordreverse(s) when 3 then print "hello" else print "You gave me #{option} -- I have no idea what to do