swap

This question already has an answer here: Java method to swap primitives 7 answers I am new to java. How to write the java equivalent of the following C code. void Swap(int *p, int *q) { int temp; temp = *p; *p = *q; *q = temp; } Here is one trick: public static int getItself(int itself, int dummy) { return itself; } public static void main(String[] args) { int a = 10; int b = 20; a = getItself(b, b = a); } Sorting two ints The short answer is: you can't do that, java has no pointers. But here's something similar that you can do: public void swap(AtomicInteger a, AtomicInteger b){ // look mom,

What is the proper way to enable my swap in STL algorithms? 1) Member swap . Does std::swap use SFINAE trick to use the member swap . 2) Free standing swap in the same namespace. 3) Partial specialization of std::swap . 4) All of the above. Thank you. EDIT: Looks like I didn't word my question clearly. Basically, I have a template class and I need STL algos to use the (efficient) swap method I wrote for that class. 1) is the proper use of swap . Write it this way when you write "library" code and want to enable ADL (argument-dependent lookup) on swap . Also, this has nothing to do with SFINAE.

I'd like to be able to swap two variables without the use of a temporary variable in C#. Can this be done? decimal startAngle = Convert.ToDecimal(159.9); decimal stopAngle = Convert.ToDecimal(355.87); // Swap each: // startAngle becomes: 355.87 // stopAngle becomes: 159.9 Willem Van Onsem First of all, swapping without a temporary variable in a language as C# is a very bad idea . But for the sake of answer, you can use this code: startAngle = startAngle + stopAngle; stopAngle = startAngle - stopAngle; startAngle = startAngle - stopAngle; Problems can however occur with rounding off if the two

I have this two variables: var a = 1, b = 2; My question is how to swap them? Only this variables, not any objects. Here's a one-liner to swap the values of two variables. Given variables a and b : b = [a, a = b][0]; Demonstration below: var a=1, b=2, output=document.getElementById('output'); output.innerHTML="<p>Original: "+a+", "+b+"</p>"; b = [a, a = b][0]; output.innerHTML+="<p>Swapped: "+a+", "+b+"</p>"; <div id="output"></div> Pedro Justo ES6 (Firefox and Chrome already support it (Destructuring Assignment Array Matching)): let a = 5, b = 6; [a, b] = [b, a]; console.log(`${a} ${b}`); You

This question already has an answer here: Transposing a 2D-array in JavaScript 17 answers For instance I have a matrix like this: |1 2 3| |4 5 6| |7 8 9| and I need it to convert into a matrix like this: |1 4 7| |2 5 8| |3 6 9| What is the best and optimal way to achieve this goal? troynt See article: Transpose An Array In JavaScript and jQuery function transpose(a) { // Calculate the width and height of the Array var w = a.length || 0; var h = a[0] instanceof Array ? a[0].length : 0; // In case it is a zero matrix, no transpose routine needed. if(h === 0 || w === 0) { return []; } /** * @var