subset

Is there a way in xts object to do the same as below but for xts object with multiple days of intraday data? The below works like a clock but for one day of data. If I pass xts from 22nd to 26th it does not. It seems like subseting intraday data in xts across multiple days is not possible to be done in one go but rather need to first split data per each day and then use this xts functionality. Is this correct? indexTZ(tdata) = "GMT" plotdata= tdata['20110822 10:00:00/20110822 12:00:00'] > plotdata= tdata['10:00:00/12:00:00'] works like swiss clock > tail(plotdata) SYMBOL EX PRICE SIZE COND

算法分类 分类及每个类型的经典题目： Pattern: Sliding window，滑动窗口类型 经典题目： Maximum Sum Subarray of Size K (easy) Smallest Subarray with a given sum (easy) Longest Substring with K Distinct Characters (medium) Fruits into Baskets (medium) No-repeat Substring (hard) Longest Substring with Same Letters after Replacement (hard) Longest Subarray with Ones after Replacement (hard) Pattern: two points, 双指针类型 经典题目： Pair with Target Sum (easy) Remove Duplicates (easy) Squaring a Sorted Array (easy) Triplet Sum to Zero (medium) Triplet Sum Close to Target (medium) Triplets with Smaller Sum (medium) Subarrays with Product

So given input = [1, 2, 3] and k=2 this would return: 1 2 1 3 2 1 2 3 3 1 3 2 This is the closest to what I am looking for, but not quite: http://algorithms.tutorialhorizon.com/print-all-combinations-of-subset-of-size-k-from-given-array/ function subsetsOfSize(a, used, startIndex, currentSize, k) { if (currentSize === k) { for (var i = 0; i < a.length; i++) { if (used[i]) console.log(a[i]); } console.log('-'); return; } if (startIndex === a.length) return; used[startIndex] = true; subsetsOfSize(a, used, startIndex+1, currentSize+1, k); used[startIndex] = false; subsetsOfSize(a, used,

I'm using the R package arules . I have some transactions and a rule (see below). I want the subset of transactions that break the rule. How can I do that? This is the set up: library(arules) data(Adult) summary(Adult) rules = apriori(Adult,parameter=list(support=0.2,confidence=0.8)) summary(rules) r=rules[1] I want the subset of transactions that contain the left hand side of the rule r but not the right hand side. The arules documentation doesn't have an example like this. I've tried %in% , match and subset but I can't get the syntax right. The documentation for the subset function has an

I want to find an algorithm that given a set A to find all groups of subsets that satisfy the following condition: x ∪ y ∪ .... z = A, where x, y, ... z ∈ Group and ∀ x,y ∈ Group: x ⊆ A, y ⊆ A, x ∩ y = ∅ = {} and ∀ x ∈ Group: x != ∅ Note: I hope to define it well, I'm not good with math symbols I made the following approach to search groups of two subsets only: from itertools import product, combinations def my_combos(A): subsets = [] for i in xrange(1, len(A)): subsets.append(list(combinations(A,i))) combos = [] for i in xrange(1, 1+len(subsets)/2): combos.extend(list(product(subsets[i-1],

This issue appeared when I was answering this question . It should be some stupid error I am doing, but I can't get what error it is… myMatrix = [22 33; 44 55] Returns: >> subsref(myMatrix, struct('type','()','subs',{{[1 2]}} ) ); ans = 22 44 While using it with cells: myCell = {2 3; 4 5} Returns: >> subsref(myCell,struct('type','{}','subs',{{[1 2]}} ) ); ans = 2 % WHATTT?? Shouldn't this be 2 and 4 Matlab?? Checking the subsref documentation , we see: See how MATLAB calls subsref for the expression: A{1:2} The syntax A{1:2} calls B = subsref(A,S) where S.type='{}' and S.subs={[1 2]}. This

This question already has answers here : How to select the row with the maximum value in each group (10 answers) Closed 2 years ago . >ID<-c('A', 'A', 'A', 'B', 'B', 'B', 'C', 'C', 'C', 'C', 'C') >WK<-c(1, 2, 3, 1, 2, 3, 1, 2, 3, 4, 5) >NumSuccess<-c(0, 0, 2, 0, 0, 1, 0, 0, 0, 0, 3) >Data<-data.frame(ID, WK, NumSuccess) I am trying to create a subset data.frame "Data2" based on the value in "NumSuccesses" that corresponds to the Max Value in "WK" grouped by "ID". Resulting data.frame should look like this: >ID<-c('A','B','C') >WK<-c(3, 3, 5) >NumSuccess<-c(2, 1, 3) >Data2<-data.frame(ID, WK,