sublist

How to remove the items in a list that are in a second list in python?

限于喜欢 提交于 2019-12-12 06:46:00
问题 I have a list of lists, and another list, and I want to remove all of the items from the list of lists that are in the second list. first = [[1,3,2,4],[1,2],[3,4,2,5,1]] to_remove = [1,2] How would I go about doing this problem in general? There are also similar questions on here but nothing has helped. 回答1: An elegant solution using sets : first = [[1,3,2,4],[1,2],[3,4,2,5,1]] to_remove = [1,2] result = [list(set(x).difference(to_remove)) for x in first] result [[3, 4], [], [3, 4, 5]] 回答2:

Java Paginated List

馋奶兔 提交于 2019-12-12 02:49:29
问题 I have 3 List of different kind of Objects . For example: List A contains 64 elements. List B contains 33 elements. List C contains 515 elements. So in total, I have 612 elements. I want to make groups ( Pagination ) of 100 elements, for example, it would look like this: Page 1 : List A : 64 elements / List B : 33 elements / List C : 3 elements Page 2 : List A : 0 elements / List B : 0 elements / List C : 100 elements Page 3 : List A : 0 elements / List B : 0 elements / List C : 100 elements

python multiply each item in sublists by a list

房东的猫 提交于 2019-12-11 04:48:16
问题 I have a list of sublists, such as this: t = [ [1, 2, 3, 4], [2, 5, 7, 9], [7, 9, 11, 4] ] I want to multiply each of the sublists by a list such that the first item in each sublist is multiplied by the first item in the multiplier list, the second item in each sublist is multiplied by the second item in the multiplier list, etc. The multiplier list is: multiplier = [0.1, 0.3, 0.5, 0.8] So that the ultimate result would be something like: result = [ [0.1, 0.6, 1.5, 3.2], [0.2, 1.5, 3.5, 7.2],

linked list sublist method-java

橙三吉。 提交于 2019-12-11 03:24:36
问题 I am attempting to write a subList method, which returns a list consisting of the current object list inclusively between indexes fromIndex and toIndex . For example, if I had list consisting of 3 5 7 9 11 20 23 and I called subList(0,3) , I should get a new list of 3 5 7 9 returned. I am using helper methods to assist in writing the method. My logic in writing this method is that I assign the head node to to be the node at index fromIndex while assigning the last node in the list to the node

How can I make sublists from a list based on strings in python?

走远了吗. 提交于 2019-12-11 03:09:26
问题 I have a list like this: ['<text id="32a45" language="ENG" date="2017-01-01" time="11:00" timezone="Eastern">', '<text id="32a47" language="ENG" date="2017-01-05" time="1:00" timezone="Central">', '<text id="32a48" language="ENG" date="2017-01-07" time="3:00" timezone="Pacific">'] From this I want to make sublists like: id = ["32a45", "32a47", "32a48"] date=["2017-01-01", "2017-01-05", "2017-01-07"] How can I do that? Thanks. Edit: This was the original question It is a broken xml file and

Sublist Arraylist in android

我的未来我决定 提交于 2019-12-11 01:33:35
问题 I want to sublist an arraylist and store it in small arraylists. I am doing as following but unable to enter exact values in the small arrays.Please see my code and suggest some other way or tell me what i am doing wrong ArrayList<ques_details> queslist = new ArrayList<ques_details>(); ArrayList[] resgrp = new ArrayList[queslist.size() / 2]; Log.v("length", resgrp.length + ""); for (int i = 0; i < resgrp.length ; i++) { resgrp[i] = new ArrayList(); Log.v("initialised ", i + ""); } for (int i

python list and sublist

泄露秘密 提交于 2019-12-10 11:43:46
问题 I have to check if list1 is contained in list2. It also should check if it appears in that order in the list as well. If it's true, it should return true and false if it doesn't. def check(lst1, lst2): for x in lst1: for y in lst2: xx = lst1.sort() yy = lst2 if xx != yy: return False else: return True I'm confusing myself with the for loops and also, I don't know where to go from here to fix my code. Pointers please? example of what it should do: check([4,0],[9,1,4,6,8,9]) True check([1,2],[2

How do I reverse a sublist in a list in place?

纵饮孤独 提交于 2019-12-09 16:02:42
问题 I'm supposed to create a function, which input is a list and two numbers, the function reverses the sublist which its place is indicated by the two numbers. for example this is what it's supposed to do: >>> lst = [1, 2, 3, 4, 5] >>> reverse_sublist (lst,0,4) >>> lst [4, 3, 2, 1, 5] I created a function and it works, but I'm not sure is it's in place. This is my code: def reverse_sublist(lst,start,end): sublist=lst[start:end] sublist.reverse() lst[start:end]=sublist print(lst) 回答1: def reverse

How to process a string into layer of sublists

早过忘川 提交于 2019-12-08 19:16:36
问题 This is the example form, I'll try to explain it in words later. I have a list from breaking up a string... say [a, a, a, b, a, a, b, a, c, a, b, a, a, c, a, c, a] where b is criteria 1 and c is criteria 2 I want to break it into a list like this: [a, a, a, [b, a, a, [b, a, c], a, [b, a, a, c], a, c], a] So I want to process the string such that when I go through it, if the item matches criteria 1, open a new list, if item matches criteria 2, close the list and return one level above. I've

Convert Hierarchical DataTable to Json

ε祈祈猫儿з 提交于 2019-12-04 15:55:33
问题 I have a hierarchial data table as follows which generates menu and its sub menus. main menu has parentId as 0. Submenu has parent Ids referring to parentId. ResourceId DisplayName ParentId Url ----------------------------------------------- 1 Home 0 Some Url 2 Student 0 Some Url 3 Staff 0 Some Url 4 Library 0 Some Url 6 StudentAtt 1 Some Url 7 TimeTable 1 Some Url 8 Staff Att 2 Some Url 9 Book Issue 3 Some Url 10 Book Return 3 Some Url 11 Fee Payment 4 Some Url 12 Book fine 10 Some Url need