strtok

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have the following code: #include #include int main (void) { char str[] = "John|Doe|Melbourne|6270|AU"; char fname[32], lname[32], city[32], zip[32], country[32]; char *oldstr = str; strcpy(fname, strtok(str, "|")); strcpy(lname, strtok(NULL, "|")); strcpy(city, strtok(NULL, "|")); strcpy(zip, strtok(NULL, "|")); strcpy(country, strtok(NULL, "|")); printf("Firstname: %s\n", fname); printf("Lastname: %s\n", lname); printf("City: %s\n", city); printf("Zip: %s\n", zip); printf("Country: %s\n", country); printf("STR: %s\n", str); printf(

C语言中没有显示的字符串数据类型，字符串以字符串常量或者字符数组的形式出现，字符串常量适用于那些程序不会对它们进行修改的字符串。所有其它字符串都必须存储于字符数组或动态分配的内存中。 字符串 是一串零个或多个字符，并且以一个位模式为全0的NULL字节结尾。 字符串所包含的的字符内部不能出现NULL字节。 NULL字节是字符串的终结符，但它并不是字符串的一部分，所以字符串的长度并不包含NULL字节。 字符串函数的声明都在 string.h 头文件中。 字符串的长度就是它所包含的字符个数，通常使用函数 strlen 来计算字符串的长度。 sizet_t strlen ( char const * string ); size_t 定义在 stddef.h 中，它是一个无符号整数类型。 在表达式中使用无符号数可能导致不必要的结果，如下： if ( strlen ( x ) >= strlen ( y ))... if ( strlen ( x ) - strlen ( y ) >= 0 )... 第二条语句的结果永远为真，因为strlen(x)、strlen(y)的返回值都是无符号数，所以>=左边是无符号数，无符号数不可能小于零。 最常用的字符串函数都是不受限制的，就是说它们只是通过寻找字符串参数结尾的NULL来判断它的长度。在使用这些函数时，必须要 保证结果字符串不会溢出内存。

I am designing a c++ program, somewhere in the program i need to detect if there is a blank(empty token) next to the token used know eg. if(token1==start) { token2=strtok(NULL," "); if(token2==NULL) {LCCTR=0;} else {LCCTR=atoi(token2);} so in the previous peice token1 is pointing to start , and i want to check if there is anumber next to the start , so I used token2=strtok(NULL," ") to point to the next token but unfortunattly the strtok function cannot detect empty spaces so it gives me an error at run time"INVALID NULL POINTER" how can i fix it or is there another function to use to detect

This question already has an answer here: strtok behavior 2 answers I am trying to use strtok() . Following is the piece of code that I wrote. It does not work but prints ", '" infinitely. #include<stdio.h> #include<stdlib.h> #include<string.h> int main(){ char str[]="this, by the way, is a 'sample'"; char *tokens; tokens = strtok(str, ", '"); //printf("%s\n",tokens); //printf("%s\n", str); while(tokens!=NULL) { printf("%s\n", tokens); tokens = (NULL, ", '"); } return 0; } Following is the code from a strtok() manual page, which works perfectly fine. #include <stdio.h> #include <string.h> int

I am trying to parse input file (containing a text document with multiple lines and delimiters, i.e. "!,.?") into words. My function 'splitting function' is: int splitInput(fp) { int i= 0; char line[255]; char *array[5000]; int x; while (fgets(line, sizeof(line), fp) != NULL) { array[i] = strtok(line, ",.!? \n"); printf("Check print - word %i:%s:\n",i, array[i]); i++; } return 0; } Here's the corrected function [sorry for extra the style cleanup]: int splitInput(fp) { int i = 0; char *cp; char *bp; char line[255]; char *array[5000]; int x; while (fgets(line, sizeof(line), fp) != NULL) { bp =

I get this error whenever i run the program " Assignment makes pointer from Integer without a cast". My code is written below.... Please help... Thankx struct student { char studentID[6]; char name[31]; char course [6]; }; struct student *array[MAX]; struct student dummy; int recordCtr=0; int read(){ FILE *stream = NULL; int ctr; char linebuffer[45]; char delims[]=", "; char *number[3]; char *token = NULL; stream = fopen("student.txt", "rt"); if (stream == NULL) stream = fopen("student.txt", "wt"); else { printf("\nReading the student list directory. Wait a moment please..."); while(!feof