strptime

I have a large data set with a variety of Date information in the following formats: DAYS since Jan 1, 1900 - ex: 41213 - I believe these are from Excel http://www.kirix.com/stratablog/jd-edwards-date-conversions-cyyddd YYDayofyear - ex 2012265 I am familiar with python's time module, strptime() method, and strftime () method. However, I am not sure what these date formats above are called on if there is a python module I can use to convert these unusual date formats. Any idea how to get the %Y%M%D format from these unusual date formats without writing my own calculator? Thanks. You can try

I have some data that looks like this: dates <- structure(c(1L, 2L, 4L, 3L), .Label = c("Sat, 18 Nov 2017 00:00:00 GMT", "Thu, 16 Nov 2017 00:00:00 GMT", "Tue, 14 Nov 2017 00:00:00 GMT", "Wed, 15 Nov 2017 00:00:00 GMT"), class = "factor") I would like to convert it to a date format instead of having it as a factor. Additionally, I want to strip the 00:00:00 GMT because it is meaningless I tried lubridate but I'm having troubles with the format: library(lubridate) mdy(dates) Warning message: All formats failed to parse. No formats found. This looks like it is working: as.POSIXct(dates, format =

I am new to C. When I practicing C to covert time sting to structure tm back and forth. I noticed some difference. Please advice what I did wrong. #include <string.h> #include <stdio.h> #include <time.h> /* test different format string to strptime " %A, %b %d, %X %z %Y " " %A, %b %d, %X %Z %Y " */ int main(int argc,char *argv[]) { char date[] = "6 Mar 2001 12:33:45"; char fmt[80]; struct tm tm; if (argc==1) return 0; strcpy(fmt,argv[1]); memset(&tm, 0, sizeof(struct tm)); if (strptime(date,"%d %b %Y %H:%M:%S",&tm)==NULL) printf("error\n"); char buf[128]; strftime(buf, sizeof(buf), fmt, &tm);

I have a problem with using strptime() function in c++. I found a piece of code in stackoverflow like below and I want to store string time information on struct tm. Although I should get year information on my tm tm_year variable, I always get a garbage.Is there anyone to help me ? Thanks in advance. string s = dtime; struct tm timeDate; memset(&timeDate,0,sizeof(struct tm)); strptime(s.c_str(),"%Y-%m-%d %H:%M", &timeDate); cout<<timeDate.tm_year<<endl; // in the example below it gives me 113 cout<<timeDate.tm_min<<endl; // it returns garbage **string s will be like "2013-12-04 15:03"** cout<

I am working with .csv data that was exported from Teradata. Several columns were originally timestamps with timezones, so after loading the .csv in R I'd like to convert these columns (which are loaded as strings) to POSIXlt or POSIXct. I am using strptime , but the format of the timezone from the .csv file does not match what strptime is expecting. For example, it expects -0400 but the .csv has the format -04:00 where a colon separates the hours and minutes. I can remove the colon, but this is an extra step and complication I'd like to avoid if possible. Is there a way to tell strptime to

Typing man strptime it sais that this function needs to have declared _XOPEN_SOURCE and included time.h header. I did it. But, when I try to compile my code I get: ./check.c:56: warning: implicit declaration of function ‘strptime’ Look at my code: int lockExpired(const char *date, const char *format, time_t current) { struct tm *tmp = malloc(sizeof(struct tm *)); time_t lt; int et; strptime(date, format, tmp); lt = mktime(tmp); et = difftime(current, lt); if (et < 3600) return -et; return 1; } Also the function declaration is: char *strptime(const char *s, const char *format, struct tm *tm);