strong-typing

问题 What is meant by strongly typed datasets in .Net? Can anybody explain with a clear and brief example? And also, what is the difference between strongly typed and weakly typed datasets? 回答1: Strongly Typed Datasets are generated on the basis of a Db Schema. They consists of classes derived form DataSet, DataTable and DataRow. Db Columns become correctly typed properties of the TableRow derived class. An Untyped Dataset simply means the direct use of Dataset, not of a descendant. All column

问题 Since PHP7 we can now use scalar typehint and ask for strict types on a per-file basis. Are there any performance benefits from using these features? If yes, how? Around the interwebs I've only found conceptual benefits, such as: more precise errors avoiding issues with unwanted type coercion more semantic code, avoiding misunderstandings when using other's code better IDE evaluation of code 回答1: Today, the use of scalar and strict types in PHP7 does not enhance performance. PHP7 does not

问题 I've a view with a strong type. This strong type has a field consisting of a byte[], this array contains a picture. Is it possible to display this image with something like @Html.Image(Model.myImage) ? Thank you very much 回答1: You can create a controller action method that returns an image as a FileContentResult: public FileContentResult Display(string id) { byte[] byteArray = GetImageFromDB(id); return new FileContentResult(byteArray, "image/jpeg"); } Then you can create an ActionLink to the

问题 I'd love to be able to do this: class myInt : public int { }; Why can't I? Why would I want to? Stronger typing. For example, I could define two classes intA and intB , which let me do intA + intA or intB + intB , but not intA + intB . "Ints aren't classes." So what? "Ints don't have any member data." Yes they do, they have 32 bits, or whatever. "Ints don't have any member functions." Well, they have a whole bunch of operators like + and - . 回答1: Neil's comment is pretty accurate. Bjarne

问题 Also, does one imply the other? 回答1: What is the difference between a strongly typed language and a statically typed language? A statically typed language has a type system that is checked at compile time by the implementation (a compiler or interpreter). The type check rejects some programs, and programs that pass the check usually come with some guarantees; for example, the compiler guarantees not to use integer arithmetic instructions on floating-point numbers. There is no real agreement

问题 What's the reason for typedefs not being strongly typed? Is there any benefit I can't see or is it due to backward compatibility? See this example: typedef int Velocity; void foo(Velocity v) { //do anything; } int main() { int i=4; foo(i); //Should result in compile error if strongly typed. return 0; } I am not asking for workarounds to get a strong typed datatype but only want to know why the standard isn't requiring typedefs to be strongly typed? Thank you. 回答1: Because C is not strongly

问题 I can't figure out how to define the object used in my LINQ grouping query to allow them to be strongly type. I've build a grouping query that uses two complex objects as keys. The query works, but I would like to be able to declare the return object type. I have a complex type... Public Class Student Public Name As IndividualsName Public EnrolledSchool As School Public BirthHospital As BirthPlace Public Grade As Integer Public Sub New(ByVal name As IndividualsName, ByVal enrolledSchool As

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I do not know how many faces this problem. If I do programming in weakly/dynamically typed language like python,php,javascript for few days I lose touch with strongly typed languages like c++,Java,.net. I recently heard languages like python and ruby which people loved programming in. It is very easy programming

问题 When I specify form inputs with the @Html.TextBoxFor method, then the generated input element would not necessarily map to the type that is expected in the form's action method. Let's say I have two classes: public class HomeA { public int A { get; set; } } public class HomeB { public int B { get; set; } } HomeA is the model of my view. If a controller action expects HomeB, then I can't provide the necessary input element in a strongly typed manner in my form: @using (Html.BeginForm()) {

问题 I'm using fastify with plugin fastify-static. I also provide my own TypeScript types declaration for this plugin in typings/fastify-static/index.d.ts : declare module "fastify-static" { import { Plugin } from "fastify"; import { Server, IncomingMessage, ServerResponse } from "http"; namespace fastifyStatic { const instance: Plugin<Server, IncomingMessage, ServerResponse, any>; } export = fastifyStatic.instance } Additionally plugin extends fastify FastifyReply with method sendFile . When I