string-parsing

问题 Here's the basic idea of what I need to do. I have two tables like the following: Table A Table B |id|name | |id|sentence | |1 |hello | |1 |I like to say hello | |2 |world | |2 |The world is large | |3 |hello world| |3 |lorem hello ipsum world lorem ipsum hello world| I need to cycle through the rows in Table A to look for each name in Table B. Then I want to use a REGEXP in Table B to replace the word if it is found. For example if hello is found in Table B it will replace the word hello in

问题 My problem is quite simple, i am parsing a CSV file, line after line and i want to get the values of the columns. The separators used are simply " ; ", but my file can have quite a lot of columns, and they won't be always in the same order. So as example for my .CSV file : time;columnA;columnB,ColumnC 27-08-2013 14:43:00; this is a text; this too; same here And i would like to be able to get all the values of time, columnA, columnB and columnC. What would be the easiest way? I used

问题 My code is posted below. I want to be able to parse using the delimiters " ()," and convert the strings into integers in cpp. while(getline(fin, line)) { x = atoi((strtok(line.c_str(),'(,)')); xx = atoi((strtok(NULL,"(),")); xxx = atoi((strtok(NULL,"(),"))); cout << x << " " << xx << " " << xxx << "\n"; } but for some reason I get the following errors GraphTest.cpp:134: error: invalid conversion from ‘const char*’ to ‘char*’ GraphTest.cpp:134: error: initializing argument 1 of ‘char* strtok

问题 I am trying to split a string without regex in a more idiomatic functional approach. case class Parsed(blocks: Vector[String], block: String, depth: Int) def processChar(parsed: Parsed, c: Char): Parsed = { import parsed._ c match { case '|' if depth == 0 => parsed.copy(block = "", blocks = blocks :+ block , depth = depth) case '[' => parsed.copy(block = block + c, depth = depth + 1) case ']' if depth == 1 => parsed.copy( block = "", blocks = blocks :+ (block + c), depth = depth - 1) case ']'

问题 I want to parse the file names of multiple doc files (MS office) using java. How should I go about doing this? I was able to find an API on extracting info from the doc itself, but I can't find information on the file name itself. So say I have a doc file XX_232312_22 , I want to just parse the file name (ie 232312 part). EDIT: What would we do if we need to parse more than just one file? For instance, all 1000 files in one directory? 回答1: String[] parts = filename.split("-"); parts[0] //

问题 I have a file which consists of the groups of lines. Each group represents a event. The end of the group is denoted by "END". I can think of using a for loop to loop through the lines, store the intermediate lines and emit the group when "END" is encounter. But since I would like to do it in Scala. I am wondering if someone can suggest a more functional way to accomplish the same thing? ---------- A B C END ---------- D E F END ---------- 回答1: Just define an iterator to return groups def

问题 I need to retrieve a large amount of data (coordinates plus an extra value) via AJAX. The format of the data is: -72.781;;6,-68.811;;8 Note two different delimiters are being used: ;; and , . Shall I just return a delimited string and use String.split() (twice) or is it better to return a JSON string and use JSON.parse() to unpack my data? What is the worst and the best from each method? 回答1: Even if the data is really quite large, the odds of their being a performance difference noticeable

问题 I know how to get the URL of the page, but how can I extract simply the domain and the domain alone? It must return the same value with or without www, and it must also return the same value regardless of file, with or without trailing slash, etc. So www.domain.com would return domain.com , and domain.com/index.php would return the same as well. Is this possible? If so, is there a way to do it without calling ExternalInterface.call('window.location.href.toString') ? Thank you for the help!

问题 Given a data file delimited by space, 10 10 10 10 222 331 2 3 3 4 45 4 2 2 4 How to read this file and load into an Array Thank you 回答1: var fileContent = File.ReadAllText(fileName); var array = fileContent.Split((string[])null, StringSplitOptions.RemoveEmptyEntries); if you have numbers only and need a list of int as a result, you can do this: var numbers = array.Select(arg => int.Parse(arg)).ToList(); 回答2: It depends on the kind of array you want. If you want to flatten everything into a

问题 I found Greg Reda's blog post about scraping HTML from nba.com: http://www.gregreda.com/2015/02/15/web-scraping-finding-the-api/ I tried to work with the code he wrote there: import requests import json url = 'http://stats.nba.com/stats/leaguedashteamshotlocations?Conference=&DateFr' + \ 'om=&DateTo=&DistanceRange=By+Zone&Division=&GameScope=&GameSegment=&LastN' + \ 'Games=0&LeagueID=00&Location=&MeasureType=Opponent&Month=0&OpponentTeamID' + \ '=0&Outcome=&PORound=0&PaceAdjust=N&PerMode