string-literals

I have multiple PHP variables in the form $number1, $number2, $number3 and so on... I would like to dynamically reference these inside of a loop to retrieve information from them, but am not sure how to reference the static variable dynamically. Ex: for($i = 1; $i <= 10; $i++) { //The first number to be printed should be the value from //$number1 not $number concatenated to $i //here are some of the strings I tried: echo "$number$i"; echo "{$number}$i"; echo "{$number}{$i}"; } This should do it: echo ${"number{$i}"}; But why not use arrays instead? Having $number[$i] is much more readable...

I know the triple quote strings are used as docstrings, but is there a real need to have two string literals? Are there any use case when identifying between single-line & multi-line is useful. in Clojure we have 1 string literal, is multi-line and we use it as docstring. So why the difference in python? The advantage of having to be explicit about creating a multi-line string literal is probably best demonstrated with an example: with open("filename.ext) as f: for line in f: print(line.upper()) Of course, any decent syntax-highlighting editor will catch that, but: It isn't always the case

So the compiler tells me this is a deprecated conversion from a string-literal to char*: char* myString = "i like declaring strings like this"; Should I be worried about this? Is this the wrong way to do this? I need to pass myString to a function that accepts a char* , who should I properly initialize the char* without this conversion? It shouldn't even compile. If you need to pass it to function that you are sure won't change the string you need to use const cast, its one of its correct uses: functionName(const_cast<char *>("something")); Or if you don't want the const cast, you can copy the

Many a times I have seen the following statements: char* ch = "Hello" cout<<ch; The output I get is " Hello ". I know that ch points to the first character of the string "Hello" and that "Hello" is a string literal and stored in read only memory. Since, ch stores the address of the first character in the string literal, so shouldn't the statement, cout<<ch; give the output " the address of a character " because, it is a pointer variable? Instead it prints the string literal itself. Moreover, if I write this, ch++; cout<<ch; It gives the output, " ello ". And similarly, it happens with more

As a follow-up on Is it mandatory to escape tabulator characters in C and C++? (do note I'm not the author of said question). I've learned such code is considered "bad practice". The comments seem to be suggesting the same thing. However, for some reason the standard allows this trickery so somebody must either found no harm in it or has a use-case for it. Is not escaping tabulator characters widely accepted as "bad practice"? Using tabs in litterals instead of escaping them ( '\t' ,"\t") is a bad practice because : the reader is not immediately aware that there is a tab. Consequence: wrong

It is valid in C and C++ to break a string literal because the preprocessor or the compiler will concatenate adjacent string literals. const char *zStr = "a" "b"; // valid What happens when string literals are prefixed with L (wide characters), u (UTF-16), U (UTF-32), u8 (UTF-8), and raw string literals ( R"foo(this is a "raw string literal" with double quotes)foo" )? For example, is the following allowed: const wchar_t *zStr = L"a" "b"; // valid? In C++0x your example is valid according to [lex.string]/p13: ... If one string literal has no encoding-prefix, it is treated as a string literal of