string-literals

What is the difference between char* and int* ? Sure, they are of different types, but how is it that I can write char* s1="hello world"; as "hello world" it is not a one character, it's an array of characters, and I cannot write *s1 as char* s1 = {'h','e','l','l','o',' ','w','o','r','l','d'}; and int* a = {2,3,1,45,6}; What is the difference? It is quite simple: A string literal, i.e., "foobar" is compiled to an array of chars which is stored in the static section of your program (i.e., where all constants are stored) and null terminated. Then, assigning this to a variable simply assigns a

This question already has answers here : Closed 6 years ago . Why is passing a string literal into a char* argument only sometimes a compiler error? (6 answers) void f(char* p) {} int main() { f("Hello"); // OK auto p = "Hello"; f(p); // error C2664: 'void f(char *)' : cannot convert parameter 1 // from 'const char *' to 'char *' } The code was compiled with VC++ Nov 2012 CTP. §2.14.15 String Literals, Section 7 A narrow string literal has type “array of n const char”, where n is the size of the string as defined below, and has static storage duration. Why is f("Hello") OK? This behaviour

So a bit of a weird question I was having trouble coming up with the search terms for. If I have a multi-line string literal in my program, is there anyway to keep the indentation of my code consistent without adding unwanted white space to my string literal? Ex: if (true) { if (!false) { //Some indented code; stringLiteral = string.format( @"This is a really long string literal I don't want it to have whitespace at the beginning of each line, so I have to break the indentation of my program I also have vars here {0} {1} {2}", var1, var2, var3); } } It's probably just my OCD talking, but is

Is there a general Scala utility method that converts a string to a string literal? The simple lambda function "\"" + _ + "\"" only works for strings without any special characters. For example, the string \" (length 2) should be converted to the string "\\\"" (length 6). Have a look at Apache Common's StringEscapeUtils class ( docs here ). escapeJava should get the job done. Have a look at this example to see it in action (in Java). Wrap the String with 3 quotes to represent it as is.. e.g. val str = """ \" """ // str : java.lang.String = \" 来源： https://stackoverflow.com/questions/17341079

So, I'm wanting to get a better grasp on how string literals in C++ work. I'm mostly concerned with situations where you're assigning the address of a string literal to a pointer, and passing it around. For example: char* advice = "Don't stick your hands in the toaster."; Now lets say I just pass this string around by copying pointers for the duration of the program. Sure, it's probably not a good idea, but I'm curious what would actually be going on behind the scenes. For another example, let's say we make a function that returns a string literal: char* foo() { // function does does stuff