string-length

How can I get the number of characters of a string in Go? For example, if I have a string "hello" the method should return 5 . I saw that len(str) returns the number of bytes and not the number of characters so len("£") returns 2 instead of 1 because £ is encoded with two bytes in UTF-8. You can try RuneCountInString from the utf8 package. returns the number of runes in p that, as illustrated in this script : the length of "World" might be 6 (when written in Chinese: "世界"), but its rune count is 2: package main import "fmt" import "unicode/utf8" func main() { fmt.Println("Hello, 世界", len("世界")

I am a C student in VBScript coding and need a little help. My code executes a split command as follows: outputArray = split(Description," ") With the individual words from Description now in an array, I want to sort the array based on the string length for each word. So, for example, if Description is equal to "this is an example of a description" then my array values are [this, is, an, example, of, a, description], right? But I want to resort the array so that the longest words are first, i.e. the array items are ordered by string length. So, after some VBScript code that I can't seem to

I have read that use of strlen is more expensive than such testing like this: We have a string x 100 characters long. I think that for (int i = 0; i < strlen(x); i++) is more expensive than this code: for (int i = 0; x[i] != '\0'; i++) Is it true? Maybe the second code will not work in some situation so is it better to use the first? Will it be better with the below? for (char *tempptr = x; *tempptr != '\0'; tempptr++) for (int i=0;i<strlen(x);i++) This code is calling strlen(x) every iteration. So if x is length 100, strlen(x) will be called 100 times. This is very expensive. Also, strlen(x)

I'm having a problem trying to get a character count column of the string values in another column, and haven't figured out how to do it efficiently. for index in range(len(df)): df['char_length'][index] = len(df['string'][index])) This apparently involves first creating a column of nulls and then rewriting it, and it takes a really long time on my data set. So what's the most effective way of getting something like 'string' 'char_length' abcd 4 abcde 5 I've checked around quite a bit, but I haven't been able to figure it out. Pandas has a vectorised string method for this: str.len() . To

How to find the length of a string (number of characters in a string) without splitting it in R? I know how to find the length of a list but not of a string. And what about Unicode strings? How do I find the length (in bytes) and the number of characters (runes, symbols) in a Unicode string? Related Question: How to find the "real" number of characters in a Unicode string in R See ?nchar . For example: > nchar("foo") [1] 3 > set.seed(10) > strn <- paste(sample(LETTERS, 10), collapse = "") > strn [1] "NHKPBEFTLY" > nchar(strn) [1] 10 Use stringi package and stri_length function > stri_length(c(

I have been using C for quite sometime, and I have this trivial problem that I want to query about. Say i want to create a character array that stores upto 1000 characters. Now, when I am using malloc for the same, then do I specify the size of array as 1001 character [ 1000 characters + null] or just 1000? Also, say I came across this problem, then how could I have found the answer to this solution on my own, maybe by using some test programs. I understand the size of string is calculated without the null character, but when I am allocating the memory for the same, do I take into account the