string-interpolation

Although Django Django does not yet support Python 3, it eventually will, so I want to keep my code the more "future-proof" possible. Since Python 2.7 the string interpolation operator ( % ) is being deprecated. And I realized that every string that needs to be translated is using the % interpolation syntax. And in the Django docs there is no mention of the new str.format method (the "new" official way of string formatting)... Maybe there is a limitation of the gettext library, but I don't think so, since the string appears identical in the .PO files. The question is if I can use the new

I have a string format which includes two integer variables, each of which needs to be formatted to a variable length: int x = 1234; int y = 42; // Simplified, real values come from method outputs, so must use the variables: int xFormatDigitCount = 7; int yFormatDigitCount = 3; var xStringFormat = new string('0', xFormatDigitCount); // "0000000" var yStringFormat = new string('0' ,yFormatDigitCount); // "000" For now I only managed to get the desired format using the integer variables' .ToString() methods: var xString = x.ToString(xStringFormat); var yString = y.ToString(yStringFormat); return

A function in swift takes any numeric type in Swift (Int, Double, Float, UInt, etc). the function converts the number to a string the function signature is as follows : func swiftNumbers <T : NumericType> (number : T) -> String { //body } NumericType is a custom protocol that has been added to numeric types in Swift. inside the body of the function, the number should be converted to a string: I use the following var stringFromNumber = "\(number)" which is not so elegant, PLUS : if the absolute value of the number is strictly inferior to 0.0001 it gives this: "\(0.000099)" //"9.9e-05" or if the

How do I transform a classic string to an f-string ? : variable = 42 user_input = "The answer is {variable}" print(user_input) The answer is {variable} f_user_input = # Here the operation to go from a string to an f-string print(f_user_input) The answer is 42 An f-string is syntax , not an object type. You can't convert an arbitrary string to that syntax, the syntax creates a string object, not the other way around. I'm assuming you want to use user_input as a template, so just use the str.format() method on the user_input object: variable = 42 user_input = "The answer is {variable}" formatted