string-interpolation

LESS class name string interpolation not working

感情迁移 提交于 2019-12-29 09:41:52
问题 I am currently translating my grid into LESS, but I can't seem to figure out string interpolation. Here's helper class that is supposed to generate all my columns: .createColumns (@colNumber+1) {} .createColumns (@index) when (@index < @colNumber) { (~".col@{index}") { width: @baseWidth * @index; } .createColumns (@index + 1); } .createColumns (01); Problem is, I get error that says something is wrong with this part (~".col@{index}") . Here's the error message: ParseError: Unrecognised input

LESS class name string interpolation not working

你说的曾经没有我的故事 提交于 2019-12-29 09:41:49
问题 I am currently translating my grid into LESS, but I can't seem to figure out string interpolation. Here's helper class that is supposed to generate all my columns: .createColumns (@colNumber+1) {} .createColumns (@index) when (@index < @colNumber) { (~".col@{index}") { width: @baseWidth * @index; } .createColumns (@index + 1); } .createColumns (01); Problem is, I get error that says something is wrong with this part (~".col@{index}") . Here's the error message: ParseError: Unrecognised input

Escape quotes in string interpolation s“ALTER TABLE ${keyspace}.\”${tableName}\“”

情到浓时终转凉″ 提交于 2019-12-24 09:58:52
问题 In Scala, while querying Cassandra, this string interpolation s"ALTER TABLE ${keyspace}.\"${tableName}\" " gives me this error: error: value $ is not a member of String [INFO] val query:String=s"ALTER TABLE ${keyspace}.\"${tableName}\" ADD $colName $dataTypeAsString;" What am I doing wrong? 回答1: The \" does not work inside string interpolations. Try using strings delimited by triple quotes: s"""ALTER TABLE ${keyspace}."${tableName}" """ or escape the inner double quotes by additional ${...} :

Using positional parameter ($1,..) in psql

给你一囗甜甜゛ 提交于 2019-12-23 09:04:06
问题 I often want to copy/paste sql out of my program code and test/debug in psql and it is tedious to have to replace positional arguments with literal values. Is there a good way to convert: select * from users where name=$1 and email=$2; to: select * from users where name='troy' and email='t@me.com'; 回答1: You could use psql variables. Those are interpolated in SQL code. Per documentation: A key feature of psql variables is that you can substitute ("interpolate") them into regular SQL statements

String interpolation in Swift

痴心易碎 提交于 2019-12-22 04:35:41
问题 A function in swift takes any numeric type in Swift (Int, Double, Float, UInt, etc). the function converts the number to a string the function signature is as follows : func swiftNumbers <T : NumericType> (number : T) -> String { //body } NumericType is a custom protocol that has been added to numeric types in Swift. inside the body of the function, the number should be converted to a string: I use the following var stringFromNumber = "\(number)" which is not so elegant, PLUS : if the

Is it possible to temporarily disable Python's string interpolation?

ぃ、小莉子 提交于 2019-12-22 03:48:14
问题 I have a python logger set up, using python's logging module. I want to store the string I'm using with the logging Formatter object in a configuration file using the ConfigParser module. The format string is stored in a dictionary of settings in a separate file that handles the reading and writing of the config file. The problem I have is that python still tries to format the file and falls over when it reads all the logging-module-specific formatting flags. { "log_level":logging.debug, "log

Overloaded string methods with string interpolation

做~自己de王妃 提交于 2019-12-21 07:29:30
问题 Why does string interpolation prefer overload of method with string instead of IFormattable ? Imagine following: static class Log { static void Debug(string message); static void Debug(IFormattable message); static bool IsDebugEnabled { get; } } I have objects with very expensive ToString() . Previously, I did following: if (Log.IsDebugEnabled) Log.Debug(string.Format("Message {0}", expensiveObject)); Now, I wanted to have the IsDebugEnabled logic inside Debug(IFormattable) , and call

ruby 1.9 how to convert array to string without brackets

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-21 03:40:37
问题 My question is about how to convert array elements to string in ruby 1.9 without getting the brackets and quotation marks. I've got an array (DB extract), from which I want to use to create a periodic report. myArray = ["Apple", "Pear", "Banana", "2", "15", "12"] In ruby 1.8 I had the following line reportStr = "In the first quarter we sold " + myArray[3].to_s + " " + myArray[0].to_s + "(s)." puts reportStr Which produced the (wanted) output In the first quarter we sold 2 Apple(s). The same

Why does interpolating a const string result in a compiler error?

谁都会走 提交于 2019-12-20 16:27:10
问题 Why does string interpolation in c# does not work with const strings? For example: private const string WEB_API_ROOT = "/private/WebApi/"; private const string WEB_API_PROJECT = $"{WEB_API_ROOT}project.json"; From my point of view, everything is known at compile time. Or is that a feature that will be added later? Compiler message: The expression being assigned to 'DynamicWebApiBuilder.WEB_API_PROJECT' must be constant. Thanks a lot! 回答1: Interpolated strings are simply converted to calls to

How does string interpolation work in Kotlin?

心已入冬 提交于 2019-12-20 10:36:10
问题 Does the Kotlin compiler translate "Hello, $name!" using something like java.lang.String.format("Hello, %s!", name) or is there some other mechanism? And if I have a class like this for example: class Client { val firstName: String val lastName: String val fullName: String get() = "$firstName $lastName" } Will this getter return a cached string or will it try to build a new string? Should I use lazyOf delegate instead? I know that there will be no performance issue unless there will be