string-formatting

I've got this basic like script that I need to convert to objective c, it turns big units of money into shortened versions (ie: 1.2m, etc), I've got most of the conversion done, but the biggest problem I'm having is right at the end. The original basic code is: ; Basic Code Function ShortCash$(BigNumber) out$="" ; First, grab the length of the number L=Len(BigNumber) Letter$="" ;Next, Do a sweep of the values, and cut them down. If l<13 out$=(BigNumber/1000000000) ; For each figure, out remainder should be divided so that it leaves a 2 digit decimal number.. remainder=(BigNumber Mod 1000000000

I want to use f-string with my string variable, not with string defined with a string literal, "..." . here is my code name=["deep","mahesh","nirbhay"] user_input = r"certi_{element}" # this string i ask from user for element in name: print(f"{user_input}") This code gives output: certi_{element} certi_{element} certi_{element} But I want: certi_{deep} certi_{mahesh} certi_{nirbhay} how can I do this? f"..." strings are great when interpolating expression results into a literal , but you don't have a literal, you have a template string in a separate variable. You can use str.format() to apply

I have the need to format a decimal number as currency but I do not wish for any rounding to occur in the process. For example (example culture is en-US) Dim money = 1234.556789D money.ToString("C") ' Yields $1,234.56 (notice the rounding & truncating) money.ToString("C99") ' Yields $1,234.556789000000000000....0 -- close but not perfect, those trailing zeros are unwanted. ' I want something that would result in this... money.ToString("??") ' Yields $1,234.56789 ' likewise.... money = 0.1D money.ToString("??") ' Yields $0.10 (notice that it at least matches the culture's currency format -- two

Currently have code that looks something like; print '{: <5}'.format('test') This will pad my string with ' ' if it is less than 5 characters. If the string is more than 5 characters, I'd need the string to be truncated. Without explicitly checking the length of my string before formatting it, is there a better way to pad if less than fixed length or truncate if greater than fixed length? You can use 5.5 to combine truncating and padding so that the output will always be of length of five: '{:5.5}'.format('testsdf') # 'tests' '{:5.5}'.format('test') # 'test ' You could use str.ljust and slice